(x+3)2 = x2+6x+9
(y-4)2 = y2-8x+16
(x+3)2+(y-4)2 = x2+6x+y2-8x+25
Therefore (x+3)2+(y-4)2-4 = x2+6x+y2-8x+21
So (x+3)2+(y-4)2 -4 = 0 means (x+3)2+(y-4)2 = 22
Therefore centre at (-3,4) with radius 2.
For part b, try drawing a line through the origin and the centre of the circle and seeing where it intersects the circle.