# Integration helpWatch

#1
How would i go about integrating: (cos^2 x)/ (sin^2 x)

I thought of it was cot^2 x = (cotx)^2, therefore cosec^4 x

Then i tried.. cosx * 1/sin^2 x * cosx
=-cotxsin^2 x.

Then i gave up...

Can anyone shed some light on how i should go about doing these sorts of questions, bearing in mind i have still got 15 of them to do, which are of the same nature.

Thanks
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12 years ago
#2
Use cos^2(x) = 1 - sin^2(x) plus the integral of cosec^2(x).
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12 years ago
#3
(Original post by Srathmore)
How would i go about integrating: (cos^2 x)/ (sin^2 x)
(cos2x)/(sin2x) = (1 - sin2x)/ (sin2x)

=> (1 - sin2x)/ (sin2x) = cosec2x - 1
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