# Need Opposite Corners Multiples Rule URGENT HELP!Watch

#1
I'm doing coursework on opposite corners and have so far found out that from the end outcome/result, a 'general rule' for both squares and rectangles, which are:

Squares - n (n-1) (n-1)

Rectangles- w (L-1) (w-1) L=length, w=width

But now I have to do a third factor, and we're doing multiples, but I am completly stuck on how to formulate a general rule for multiples.

What I have done so far is use 4x4 square grids and within these I have used multiples of:
2, 3, 4, 5

From doing that I have found that the end outcomes:
(I am using a 4x4 squre grid for them all)

Multiple | Outcome
- - - 2 - - - 144
- - - 3 - - - 324
- - - 4 - - - 576
- - - 5 - - - 900

What I have seemed to notice is that all the outcomes are square numbers, but I am not sure if that is relevant to finding a general rule or not.

My maths teacher said something along the lines that is is similar to the Squares general rule, but I am completly baffled and I think if I stare any longer at it my head shall explode!

So any help would be greatly appreciated as my coursework is already a 'little' late.

I just need the general rule which I can then go on to predict other multiple squares and prove them algebraically.

Thanks!
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12 years ago
#2
hey there,

if you are just looking for the general rule between

2 ---- 144
3 ----324
4 ----576
5 ----900

the general rule is 6*n^2 ( in words "six n squared")

6*2 = 12 and 12^2 = 144
6*3 = 18 and 18^2 = 324
6*4 = 24 and 24^2 = 576
6*5 = 30 and 30^2 = 900

hope this helps.
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#3
Thank you, thank you, thank you so much! Your a star!

I can't believe it was that simple!

So the General rule is: (6xn)^2

Thanks Again!
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