On (-pi,pi), find the Fourier Series of f(x)=2x. Hence, or otherwise, find the Fourier series of g(x)=x^2.
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Fourier Series watch
- Thread Starter
- 25-02-2006 21:00
- 25-02-2006 21:10
Just use the standard definitions and formula for the fourier series of y=2x. Since it's between -pi and pi, y is odd, and therefore it'll be a sin series, with all the coefficents of cos(n pi/L) being zero.
f(x) = g'(x), so when you've the series for f(x), integrate it to give g(x).