Any predictions from tomorrow?

Do they ask one set of questions more in each session? Last time was almost all theory, so should we expect all calculations now? O.o

Reply 144

savouryjesus

Original post by Alexok

All need to know is that a neutrino has no charge. Anythig with a *blablabla neutrino* has no charge so will not show a path in a bubble chamber etc

And also remember antielectron neutrinos are emitted in beta minus decay to conserve lepton number, I think :tongue:

Could anyone explain question 5 from june 11? it's about two coils, coil X has 1000 turns and cross sectional area of 10cm^2, and has a current generating a magnetic field of 0.002 T. Coil Y looks as if it's inside it, coil Y has 50 turns and a cross sectional area of 4cm^2, what's the flux linkage with coil Y? apparently it's 4x10^-5Wb?
I just can't get my head around it :frown:

Nϕ = BAN right? D: Thanks

(edited 11 years ago)

Reply 145

yazdan

Original post by simransanghera

hey guys ,

can someone help me with q6i from the jan 2010 paper? I keep getting the wrong answer, the right answer is B.

Thanks!

Hey,
u gotta use the formula K.E= eV

so, 1/2mv^2= electron charge x Voltage

Its on page 82 of the A2 physics book
hope it helps :smile:

Reply 146

TenaciousMonkey

10

What do we need to know about transformers? I can't find any notes on it, could some go over it quickly?

Reply 147

lzyastra

Epic Video on Transformers - this guy explains it really well and how it links with electromagnetic induction .. http://youtu.be/4aYhAbzSwvs

Reply 148

lzyastra

And by the way guys I don't know why people keep talking about momentum in 3D, you don't need to know about it for this exam. I doubt we'll see a momentum question harder than the one at the end of Jan 2012 anyway..

Reply 149

King_Arthur

6

i done physics 4 and like lzyastra there is no momentum in 3D
unless you are signifying something else

Reply 150

TenaciousMonkey

10

Original post by lzyastra

Epic Video on Transformers - this guy explains it really well and how it links with electromagnetic induction .. http://youtu.be/4aYhAbzSwvs

This guy is awesome! Thanks!

Reply 151

simransanghera

Original post by yazdan

Hey,
u gotta use the formula K.E= eV

so, 1/2mv^2= electron charge x Voltage

Its on page 82 of the A2 physics book
hope it helps :smile:

Thanks! That worked! I can't believe I didnt know how to do that =/

Reply 152

simransanghera

Original post by TenaciousMonkey

What do we need to know about transformers? I can't find any notes on it, could some go over it quickly?

I've attached some notes and the last page has something about Transformers. Hope it helps!

Physics Unit 4.docx361.7KB

Reply 153

username287755

how do you do question 16 (b) ii,iii, iv...june 2011

Physics 4 June 2011 QP.pdf851.1KB

Reply 154

simransanghera

does anyone understand q 15d(i) of jan 2010? The mark scheme makes no sense once again >.<

Thanks

Reply 155

username287755

Original post by simransanghera

does anyone understand q 15d(i) of jan 2010? The mark scheme makes no sense once again >.<

Thanks

we worked out momentum before in a (ii),
since momentum = mass x velocity,
divide momentum by the mass to get the speed

Reply 156

simransanghera

Original post by Killerstorm2

we worked out momentum before in a (ii),
since momentum = mass x velocity,
divide momentum by the mass to get the speed

Thank you!

I would help on your q16 from June 2011 but i can't do it either! sorry!

All i Know is that the 'E's mean x10 power.

Reply 157

Jess!ca

2

Anyone know how to do Q6(i) on Jan 10 paper?

An electron gun uses a pd to accelerate electrons from rest to speed of 2x10^7ms
The pd is:

B) 1140V

How do you work it out?!

Reply 158

username287755

Original post by Jess!ca

Anyone know how to do Q6(i) on Jan 10 paper?

An electron gun uses a pd to accelerate electrons from rest to speed of 2x10^7ms
The pd is:

B) 1140V

How do you work it out?!

The energy that the electron gain (E=QV) is converted into KE..
So, QV = 0.5m v^2 , we know "v (speed)", "m" and "Q", so rearrange and get "V (P.D)"

Reply 159

Bourii

Original post by savouryjesus

And also remember antielectron neutrinos are emitted in beta minus decay to conserve lepton number, I think :tongue:

Could anyone explain question 5 from june 11? it's about two coils, coil X has 1000 turns and cross sectional area of 10cm^2, and has a current generating a magnetic field of 0.002 T. Coil Y looks as if it's inside it, coil Y has 50 turns and a cross sectional area of 4cm^2, what's the flux linkage with coil Y? apparently it's 4x10^-5Wb?
I just can't get my head around it :frown:

Nϕ = BAN right? D: Thanks

Use that equation, but ignore the coil on the outside as it would have no effect on the flux linkage of the coil on the inside. I think if you come to terms with what flux linkage actually is these questions are a lot simpler.

A2 6PH04 Physics Unit 4 'Physics on the Move' - 11th June 2012

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