The Student Room Group

Scroll to see replies

Original post by chignesh10
the grade boundary was 62 for jan 06, ok? capiche?


oh i get it so i scraped an A
but was the paper hard from your opinion
Reply 201
Original post by otrivine
oh i get it so i scraped an A
but was the paper hard from your opinion


Jun-05 53
Jun-01 55
Nov-03 55
Jun-10 55
Jan-05 56
Jan-01 57
Jun-04 57
Nov-04 57
Jan-09 57
Nov-02 58
Jun-07 58
Jun-06 59
Jan-11 59
Jan-04 60
Jun-08 60
Jun-09 60
Jan-12 60
Jan-07 61
Jun-11 61
Jun-03 62
Jan-06 62
Jan-08 63
Jan-10 65

These are ordered by the raw marks required to gain an A.
The higher the number, the easier the paper.
Original post by dslc
Jun-05 53
Jun-01 55
Nov-03 55
Jun-10 55
Jan-05 56
Jan-01 57
Jun-04 57
Nov-04 57
Jan-09 57
Nov-02 58
Jun-07 58
Jun-06 59
Jan-11 59
Jan-04 60
Jun-08 60
Jun-09 60
Jan-12 60
Jan-07 61
Jun-11 61
Jun-03 62
Jan-06 62
Jan-08 63
Jan-10 65

These are ordered by the raw marks required to gain an A.
The higher the number, the easier the paper.


thanks and one more question u know the examination paper question on the edexcel book the last question on part c) i got 0.375 but book is getting 0.276 ?
Reply 203
Original post by otrivine
thanks and one more question u know the examination paper question on the edexcel book the last question on part c) i got 0.375 but book is getting 0.276 ?


Is this the question about Jean and hitting the target?
Reply 204
Can anyone help me with 2b. It's from Jan 2012 I have attached the question below.

q2.gif

So far I have:

P(A u B) = P(A) + P(B) - P(A n B)
2/3 = 1/4 + P(B) - 1/4*P(B)
5/12 = P(B) - 1/4*P(B)

I have checked the mark scheme and I am correct up to this point but I am stumped on what to do next. The mark scheme jumps to:

5/12 = 3/4*P(B)

But I have no idea how P(B) - 1/4*P(B) gets to 3/4*P(B).

The answer is probably a really simple one, but if anyone can help me it would be much appreciated :smile:
Original post by Scorcher
Can anyone help me with 2b. It's from Jan 2012 I have attached the question below.

q2.gif

So far I have:

P(A u B) = P(A) + P(B) - P(A n B)
2/3 = 1/4 + P(B) - 1/4*P(B)
5/12 = P(B) - 1/4*P(B)

I have checked the mark scheme and I am correct up to this point but I am stumped on what to do next. The mark scheme jumps to:

5/12 = 3/4*P(B)

But I have no idea how P(B) - 1/4*P(B) gets to 3/4*P(B).

The answer is probably a really simple one, but if anyone can help me it would be much appreciated :smile:


Replace P(B) with "x". You now have x - 1/4*x - in other words 1x - 0.25x, which makes 0.75x, which = 3/4x.

x = P(B), therefore, P(B) - 1/4*P(B) = 3/4*P(B) :smile:

P(B) = 5/9...i hope :wink:
(edited 11 years ago)
Reply 206
Original post by knowledgecorruptz
Replace P(B) with "x". You now have x - 1/4*x - in other words 1x - 0.25x, which makes 0.75x, which = 3/4x.

x = P(B), therefore, P(B) - 1/4*P(B) = 3/4*P(B) :smile:

P(B) = 5/9...i hope :wink:


You life saver! How the hell did I not get that :confused:

Thanks for the explanation, much appreciated :smile:
Reply 207
Original post by QwertyG
wow. when did you start past papers for s1??


about 2 weeks ago. kinda regretting doing all of them so quickly cos now im close the exam.. im sort of struggling of what to do .. i dont want to not revise for s1 any more cos u cant over-revise for any subject. so any tips or links for probability questions?
Reply 208
Original post by stuck18
about 2 weeks ago. kinda regretting doing all of them so quickly cos now im close the exam.. im sort of struggling of what to do .. i dont want to not revise for s1 any more cos u cant over-revise for any subject. so any tips or links for probability questions?


wtf 2 weeks and you done all the solomon papers/2001-2011 past papers no way lol

I cant think of anymore resources lol
Reply 209
Original post by QwertyG
wtf 2 weeks and you done all the solomon papers/2001-2011 past papers no way lol

I cant think of anymore resources lol


yes way. it is possible when you do all nighters and only concentrate on s1 .. since this is my first exam. still SO scared for this exam. dont feel good about it :frown:
Reply 210
Original post by Zhy
I hope there will be lots of definition questions, conditional probability, and 8-circle Venn diagrams. It will make it fun! :smile:


oh btw what do you mean by 8-circle Venn diagrams. the only ones I am aware of are the 3 circles that intersect eachother within the sample space and the standard 2 circled venn diagrams. i cant find anything to do with 8-circle ones on google or in the text book.
Reply 211
Original post by stuck18
oh btw what do you mean by 8-circle Venn diagrams. the only ones I am aware of are the 3 circles that intersect eachother within the sample space and the standard 2 circled venn diagrams. i cant find anything to do with 8-circle ones on google or in the text book.


Wtf? 8 circles? thats nuts!
Reply 212
lawl he trolling
8 circles :redface:! New Venn diagram has just been brought to life.
Anyways can some one please explain to me Jan 12 last question part b.
If I remember correctly it was P(232<W<w)=0.2
and you had to find w given.
(232,5^2)
Cheers
Reply 214
Original post by dan94adibi
Anyways can some one please explain to me Jan 12 last question part b.
If I remember correctly it was P(232<W<w)=0.2
and you had to find w given.
(232,5^2)
Cheers


(b) You are given P(232 < W < w) = 0.2 and W~N(232,52) - the latter being composed from the information at the start of the question.
First of all you need to turn the normal distribution you are given into a standard normal distribution.

This step is as follows: P[(232-232)÷5 < Z < (w-232)÷5] = 0.2
Therefore: P[0 < Z < (w-232)÷5] = 0.2

Next you need to draw your normal distribution curve. You know that 0 will be at the mean, so the region must be between the middle of the normal distribution curve and some point to the right of it (w-232)÷5.

We know everything to the left of 0 has a probability of 0.5, so P[Z<(w-232)÷5] = 0.7. We can look this up in the table of probabilities to find that (w-232)÷5 0.52.

And so, we reach: (w-232)÷5 = 0.52.
Therefore, (w-232) = 2.6
And so, w = 234.6.

In the mark scheme you will see answers are accepted so long as they round to 235
Reply 215
Does anyone use normal distribution on their calculator to work out ND questions??
Original post by stuck18
yes way. it is possible when you do all nighters and only concentrate on s1 .. since this is my first exam. still SO scared for this exam. dont feel good about it :frown:


Don't worry, just relax and recheck all of the papers you've solved to know exactly how and why you made the mistakes you did (or you can resolve them if you have enough time). It might be a good idea to resolve some of the hard questions in the past papers or in the book too. Lastly, do NOT worry before and during the exam since you've done more than enough to get a high grade ..:smile:
Just finished the past papers ..... gotta start with the solomon papers .... :s-smilie:
Reply 217
^ where can i get the solomon papers?
Reply 218
Original post by Lindizya
^ where can i get the solomon papers?


http://www.thomas-reddington.com/s1.html
scroll down to bottom

Latest

Trending

Trending