Even functions Watch

Eau
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#1
Report Thread starter 12 years ago
#1
How do I prove that this function

g(x)=e^(sin(x + pi/2)), where x E [-2pi, 2pi]

is an even function, i.e. g(-x) = g(x)

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AlphaNumeric
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#2
Report 12 years ago
#2
sin(x+pi/2) = cos(x)
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The Orientalist
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#3
Report 12 years ago
#3
sin(pi/2+x)=sin(pi/2-x)=cos(x) thus g(x)=g(-x)
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