You are Here: Home >< Physics

# RLC parallel circuit total cuurent Watch

1. Hi
Can a kind person please check my solution? This is the question: Demonstrate the total current in an RLC parallel circuit using the following circuit. I cant draw it but the inductive reactance is 20ohms, capacitive reactance is 5ohms and resistor of 10ohms. All are in parallel. The voltage is 5v in series with 20ohms inductive reactance.
This is my attempted solution:
Resistive Branch: I = E/R = 5/10 = 0.5A
Capacitive Branch : E/Xc = 5/5 = 1A
Inductive Branch = E/XL =5/20 = 0.25A
Resultant current, Ix = 1 - 0.25 = 0.75a

Total current = (I^2R + I^2X)^1/2
= (0.75^2 + 0.5^2)^1/2 A
2. Need to see the circuit here.
3. (Original post by teachercol)
Need to see the circuit here.
Dont know how to load it. Sorry. Is the information incomplete?
4. Ok I've reread and I think I've got it.

Supply + inductive reactance then 3 branches,( one each of R L and C )

There wont be 5v acorss the branches. Some PD will be across the inductive reactance.

You're on the right lines in taking phaes differecnes into account vectorially - but then you need to add in the PD acorss the inductance in the main circuit to get 5v.

Updated: March 29, 2012
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### Grade boundaries not out until results day

What does this mean for you?

### The most OUTRAGEOUS stories from school

Poll
Study resources

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE

Reputation gems: You get these gems as you gain rep from other members for making good contributions and giving helpful advice.