differentiating ln2x

complete mind block i cant remember how to do it is it 2/2x therefore 1/x

marcusps

complete mind block i cant remember how to do it is it 2/2x therefore 1/x

Let u = 2x => du/dx = 2
Let y = ln(2x) = lnu => dy/du = 1/u
:. d/dx[ln(2x)] = (1/u) * 2 = 2/(2x) = 1/x

So yes.

Alternatively ln(2x) = ln2 + lnx. lnx is the only variable with the usual derivative.

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