Silver nitrate and chloride ions ... Watch

h1nna
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Report Thread starter 12 years ago
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Hi, i'm stuck on part of a homework question ... any help appreciated!

When a dilute aqueous solution of silver nitrate is added to an excess of conc hydrochloric acid, the white precipitate produced initially dissolves on shaking the mixture. give the formula of the white precipitate and deduce the probable formula and shape of the final silver species present once the precipitate has dissolved.

Formula of white precipitate - AgCl

Formula of final silver species in solution - Can't work this out!

Shape of final silver species in solution - Tetrahedral (i think?)

Any clarification, corrections and help especially on the middle question would be most appreciated. Thankyou in advance.
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charco
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This is formation of a complex ion by the chloride ions complexing wth the silver ion.
Ag+ + 2Cl- --> [AgCl2]-
silver forms a diammine complex wth ammonia ligands so I suspect that the chloride ions also form dichloro complex (but this is a guess!) in which case it would be linear.
There is also a possibility that the chloride ions form a tetrahedral complex in which case it would be [AgCl4]3-
When I have a moment I'll look it up.
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charco
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as far as I can tell silver only forms complexes of the type [Ag(ligand)2] so the formula would be [AgCl2]- the dichloro argentate (I) complex ion
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