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AS Maths M1 help - please!

Hi,

I'm really struggling with Mechanics 1, and I have started by trying to revise Kinematics,but I've found a few questions that I just can't do.

If anybody can help, would they please explain where they have got the numbers from, as I think that might help me to understand a bit better.

1) At time t=0 a particle is projected vertically upwards with speed u from a point 10m above the ground. At time T seconds, the particle hits the ground with speed 17.5ms-1. Find

a) the value of u

b) the value of T

The mark scheme says u is 10.5ms-1 and T is 20/7 seconds. But I cannot get to these answers.

2) A ball is thrown vertically upwards with speed 21ms-1. It hits the ground 4.5s later. Find the height above the ground from which the ball was thrown.

The answers at the back of the textbook says it should be 4.7m.

Any help would be greatly appreciated. I'm not feeling at all confident about mechanics, and don't seem to be able to pass the first chapter of the textbook :frown:

Reply 1

Ok, first of all we start with suvat

s = -10 (if the ball was 10m above the ground, then when it hits the ground it's 10m below it's starting point)
u = u
v = -17.5 (the ball was thrown upwards, so we take that as positive, but comes back down so it'll be negative)
a = -g (again it accelerates downwards)
t = T

So we know v,a and s and want to work out u. What equation do you know that connects all of them together?

Spoiler



And what equation do you know that connects v, a, s and t together?

Need more depth just shout :wink2:

Reply 2

Original post by ElMoro
Ok, first of all we start with suvat

s = -10 (if the ball was 10m above the ground, then when it hits the ground it's 10m below it's starting point)
u = u
v = -17.5 (the ball was thrown upwards, so we take that as positive, but comes back down so it'll be negative)
a = -g (again it accelerates downwards)
t = T

So we know v,a and s and want to work out u. What equation do you know that connects all of them together?

Spoiler



And what equation do you know that connects v, a, s and t together?

Need more depth just shout :wink2:


Thank you, Thank you, Thank you :smile:

I've got to u being 10.5 now - I didn't have v as a negative.

This is going to sound stupid, but for part b), when you know v, u, a and s and you want T, how do you know which equation to use?

Reply 3

And for part b, will u be negative or positive?

Reply 4

Original post by HowToSaveALife
Thank you, Thank you, Thank you :smile:

I've got to u being 10.5 now - I didn't have v as a negative.

This is going to sound stupid, but for part b), when you know v, u, a and s and you want T, how do you know which equation to use?


You can use any equation that contains T and another three values you know

I would pick the one containing v, a and s because u has been rounded to 10.5 so might affect the accuracy of your answer

Original post by HowToSaveALife
And for part b, will u be negative or positive?


Basically just pick one direction to be positive (I chose upwards) and then the other direction is negative. As long as you're consistent then it doesn't matter :smile:

Reply 5

Original post by ElMoro
You can use any equation that contains T and another three values you know

I would pick the one containing v, a and s because u has been rounded to 10.5 so might affect the accuracy of your answer



Basically just pick one direction to be positive (I chose upwards) and then the other direction is negative. As long as you're consistent then it doesn't matter :smile:


I've done it!

Could you tell me where I went wrong with question 2?

I did..
u=21
a=-9.8
t=4.5
s= S

so s=ut+1/2xat2
s = 94.5 - 99.225
s = -4.7

I need distance above ground and it is a minus :frown:

Reply 6

Original post by HowToSaveALife
I've done it!

Could you tell me where I went wrong with question 2?

I did..
u=21
a=-9.8
t=4.5
s= S

so s=ut+1/2xat2
s = 94.5 - 99.225
s = -4.7

I need distance above ground and it is a minus :frown:


You haven't made a mistake

s means the displacement of the ball

-4.7 means the ball travelled 4.7m downwards before it hit the ground

That means it was 4.7m above the ground to start with

Hope this makes sense :wink2:

Reply 7

Original post by ElMoro
You haven't made a mistake

s means the displacement of the ball

-4.7 means the ball travelled 4.7m downwards before it hit the ground

That means it was 4.7m above the ground to start with

Hope this makes sense :wink2:


You are an absolute star!

Thank you :smile:

Reply 8

Original post by ElMoro
You can use any equation that contains T and another three values you know
I would pick the one containing v, a and s because u has been rounded to 10.5 so might affect the accuracy of your answer
Basically just pick one direction to be positive (I chose upwards) and then the other direction is negative. As long as you're consistent then it doesn't matter :smile:

hi
want i did was i took u as negative as well because i took the point where the displacement of the ball was 0 so i took the situation from there.
U will be negative as it is going down and v as well and the displacement wil lalso be negative with the acceleration also negative.
is this logic correct?

Reply 9

Original post by Ajsjdhdhdh
hi
want i did was i took u as negative as well because i took the point where the displacement of the ball was 0 so i took the situation from there.
U will be negative as it is going down and v as well and the displacement wil lalso be negative with the acceleration also negative.
is this logic correct?

This thread is 12 years old so you're unlikely to get a response back

Reply 10

Original post by Ajsjdhdhdh
hi
want i did was i took u as negative as well because i took the point where the displacement of the ball was 0 so i took the situation from there.
U will be negative as it is going down and v as well and the displacement wil lalso be negative with the acceleration also negative.
is this logic correct?

Hello, so this question is from twelve years ago but quickly re-reading it:

We have: At time t=0 a particle is projected vertically upwards with speed u from a point 10m above the ground.

So I'm not sure what you mean by "U will be negative as it is going down"

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