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    good afternoon.
    hcn+naoh<->nacn+h2o
    How to displace balance to the right towards receiving salt?
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    (Original post by Hoop7)
    good afternoon.
    hcn+naoh<->nacn+h2o
    How to displace balance to the right towards receiving salt?
    If you add a greater concentration of reactants, the equilibrium will shift to the right (towards the products), in order to oppose the change and get back to the original, equilibrium concentration.

    Also, do you know whether the forward reaction (forming the products) is exothermic or endothermic?
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    Thank you -i know about Le Shatelie but I do not know how to remove reagents from the right side. Could Ethanol help? I need a clear substance.
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    If you do this reaction in water (which I assume you are) then the equilibrium will be massively towards the right hand side anyway. This is because in water [H+][OH-]=10^-14, and so if you add appreciable amounts of both H+and OH- the reaction will quickly proceed to reduce these concentrations.
 
 
 
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