lilangeldanni
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I'm a AS Level student doing MEI maths, i have found most parts of the course pretty straight forward but i missed a lot of school when logarithms and exponentials were covered. i just tried to attempt to MEI Chapter assessment and realised that i'm really struggling with understanding anything to do with logarithms other than the really simply stuff. does anyone know any good ways to learn this stuff?? many thanks.
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boromir9111
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Post a question you're struggling with and then you'll be able to get appropriate responses to your specific weak spot on this topic!
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tehforum
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See attached.

Enjoy.
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the bear
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there are plenty of online resources... for instance

http://www.themathpage.com/aprecalc/logarithms.htm
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lilangeldanni
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(Original post by the bear)
there are plenty of online resources... for instance

http://www.themathpage.com/aprecalc/logarithms.htm
this is actually what i needed, the way MEI explains stuff just goes straight over my head. cheers for this
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lilangeldanni
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http://integralmaths.org/resources/f...hms/c2lass.pdf

thats the link to the specific chapter assessment struggling on 4 part 3 i can work out what 2x is but when do i go from there? havent got any further than this but the last part will probably be even worse.
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boromir9111
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(Original post by lilangeldanni)
http://integralmaths.org/resources/f...hms/c2lass.pdf

thats the link to the specific chapter assessment struggling on 4 part 3 i can work out what 2x is but when do i go from there? havent got any further than this but the last part will probably be even worse.
Do you mind typing out the question? Can't access it from the site.
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tehforum
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(Original post by boromir9111)
Do you mind typing out the question? Can't access it from the site.
3^2x=5

Well if you've worked out 2x

log3^2x=log5
2xlog3=log5
2x= log5/log3
x = (log5/log3)/2
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lilangeldanni
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yeah i thought that was what i was to do but i wasn't sure whether it was asking me to actually work out the answer as 0.732 or whether i was just to leave it as (log5/log3)/2
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tehforum
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(Original post by lilangeldanni)
yeah i thought that was what i was to do but i wasn't sure whether it was asking me to actually work out the answer as 0.732 or whether i was just to leave it as (log5/log3)/2
3sf.

so 0.732
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itsn0b0dy
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(Original post by tehforum)
See attached.

Enjoy.
this was incredibly useful! thank you so much.

is there any chance you could tell me where you got these from, or if you could provide the links to any more topics?
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tehforum
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(Original post by itsn0b0dy)
this was incredibly useful! thank you so much.

is there any chance you could tell me where you got these from, or if you could provide the links to any more topics?
i can't remember

its part of MEI official resources that we paid for
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