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pruts
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Hello, What would be the inequalitie for the following problem,

A company can produce up to 10 truckloads per hour of X or up to 5 truckloads per hour of Y.



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Nylex
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X <= 10, Y <= 5.
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ILoveMaths
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I wish i was you, ur soooooooooooooo cool, maths is really cool? er.. no it isn't. When I'm older I actually want to be like u lot!!!! UR SOOOOOOOOOOOOOOOOOOOOOOOOO COOL!!!!!!!!!!!!!!!!!!!
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pruts
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(Original post by Nylex)
X <= 10, Y <= 5.
Hello, Did you mean to say the |X| <= 10. and |Y|<=5 or just as how you have written before.

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JamesF
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Why would you need the modulus signs? The company cant produce negative amounts.
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elpaw
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(Original post by pruts)
Hello, Did you mean to say the |X| <= 10. and |Y|<=5 or just as how you have written before.

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the company cant produce e.g. -7 goods per truckload, can they? (unless they are producing electric charges or antimatter)
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pruts
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(Original post by elpaw)
the company cant produce e.g. -7 goods per truckload, can they? (unless they are producing electric charges or antimatter)
Hello, Is it necessary to include 0 as the company could produce no Loads of X or Y .


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elpaw
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(Original post by pruts)
Hello, Is it necessary to include 0 as the company could produce no Loads of X or Y .


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yes, so the inequalities are 0<=x<=10 0<=y<=5

but are x and y linked in some way? for example, is 2 lots of x equal to one lot of y? so if they are producing 8 truckloads of x, they can only produce 1 truckload of y?
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pruts
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(Original post by elpaw)
yes, so the inequalities are 0<=x<=10 0<=y<=5

but are x and y linked in some way? for example, is 2 lots of x equal to one lot of y? so if they are producing 8 truckloads of x, they can only produce 1 truckload of y?
At this stage of the production I can deduce from the question that they are not related. But later on

they give you limits ie The trucks available can carry up to 6 loads of X per hour or up to 10 loads per hour of Y .
and so for this phase they require to work out the inequalities again. ( truck capacity measurement)

Final phase, it says no more then 7 loads per hour can be handled at the loading phase of the operation. They want inequalitiy for this as well( loading phase)


and the profit per truckload of X is $40 and per trucload of Y is $60.


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john !!
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(Original post by pruts)
Hello, What would be the inequalitie for the following problem,

A company can produce up to 10 truckloads per hour of X or up to 5 truckloads per hour of Y.



cheers
He said or, so I think this would be correct.

0< x + 2y <= 10
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elpaw
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(Original post by mik1a)
He said or, so I think this would be correct.

0< x + 2y <= 10
but then or could be strictly or. i e he can only produce x or y, not both at the same time.
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john !!
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I'm assuming that x takes half the work to produce than y. You're correct, but you have to make that assumption, because the word or means that two seperate inequalities for x and y won't ever work. x could be 10 and y could be 5 according to the first solution, which is clearly wrong.

I'm assuming there is a linear relationship.
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pruts
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(Original post by elpaw)
but then or could be strictly or. i e he can only produce x or y, not both at the same time.
Hello, The question asks to work out inequalities at each seperate production phases.


1) THe company can produce up to 10 truck loads of X per hour or up to 5 truckloads per hour of Y.

2) The trucks available can carry up to 6 loads of X per hour or up to 10 loads per hour of Y .
and so for this phase they require to work out the inequalities again. ( truck capacity measurement)

3)Final phase, it says no more then 7 loads per hour can be handled at the loading phase of the operation. They want inequalitiy for this as well( loading phase)


I think that the question implies 'AND' in statistical terms ie X AND Y can be produced. t

so therefore would the inequality 0< x + 2y <= 10 be ok for 1st phase.

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pruts
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Hello, Please sum1 clarify.
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username9816
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(Original post by pruts)
Hello, What would be the inequalitie for the following problem,

A company can produce up to 10 truckloads per hour of X or up to 5 truckloads per hour of Y.



cheers
0 <= x <= 10 OR 0 <= y <= 5
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