You are Here: Home >< Maths

# M1 projectiles, quick question

1. Part e) State the magnitude and direction of the velocity of the ball as it hits the surface.

I've worked out the magnitude (20 ms-1) but I don't understand how to work out the direction. What does '50 degrees below the horizontal' mean?
2. If you have the magnitude of the horizontal and vertical components of velocity of the ball as it hits the surface, then you can form a triangle and use simple trig to find the angle theta below the horizontal.
3. Is this correct?

Vertical velocity: y=20sin50 -9.8*3.13 = -15.4 ms-1
Horizontal velocity x = 20cos50 = 12.9 ms-1

a = tan-1 (15.4/12.9) = 50degrees

I'm still not sure what it means by 'below the horizontal'.
4. Anyone?
5. Well the horizontal is the horizontal line and your angle is below that
6. Isn't projectile motion M2?
7. (Original post by Sarabande)
Isn't projectile motion M2?
I guess it must be board dependant

It is M1 for AQA
8. (Original post by TenOfThem)
I guess it must be board dependant

It is M1 for AQA
Ah. For Edexcel it's the first kinematics topic of M2.

## Register

Thanks for posting! You just need to create an account in order to submit the post
1. this can't be left blank
2. this can't be left blank
3. this can't be left blank

6 characters or longer with both numbers and letters is safer

4. this can't be left empty
1. Oops, you need to agree to our Ts&Cs to register

Updated: April 16, 2012
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Today on TSR

### A-level exams coming up?

Find everything you need here.

Poll
Useful resources

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams