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    how would you factorise 3r^2 + 2n^2 - 10/3*n*r to make it equal r or n
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    that's an expression, you can't make anything equal anything in an expression. you need two expressions with a common relationship to make an equation.
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    how would you factorise 3r^2 + 2n^2 - 10/3*n*r = 0 to make it equal r or n
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    (Original post by silent p......?)
    how would you factorise 3r^2 + 2n^2 - 10/3*n*r = 0 to make it equal r or n
    well,to make life easier u can multiply everything by 3...........
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    (Original post by silent p......?)
    how would you factorise 3r^2 + 2n^2 - 10/3*n*r = 0 to make it equal r or n
    Are you trying to solve the equation and find values of r and n?

    And which one is the right equation?

    3r^2 + 2n^2 - (10/3)(n)(r) = 0

    OR

    3r^2 + 2n^2 - 10/(3nr) = 0
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    r or n and

    3r^2 + 2n^2 - (10/3)*nr = 0
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    (Original post by silent p......?)
    r or n and

    3r^2 + 2n^2 - (10/3)*nr = 0
    multiply by 3 to get 9r^2 + 6n^2 -10nr=0,which errrr cannot be simplified to (an+br)(cn+dr)=0
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    it's impossible?
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    (Original post by silent p......?)
    it's impossible?
    sorry to break it 2 ya
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    (Original post by silent p......?)
    r or n and

    3r^2 + 2n^2 - (10/3)*nr = 0
    9r² - 10nr +6n² = 0

    r = [10n+-√(100n²-216n)]/18
    OR
    n = [10r +-√(100r²-216r)]/12


    this only works for 0 >= n,r or n,r >= 2.16
 
 
 
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