I have a question set that im unsure with as I dont have the final answers
A DC motor is shunt wound and is supplied with 500V. The armature resistance is 1ohm and the field winding is 500ohm. The running torque is 100Nm and the motor takes 21A. Determine the speed of the motor,
My calculations so far are
Calculate armature resistance : I-If = 21 - (500/500) = 20A
calculate back EMF = V - IaRa = 500 - 20 = 480V
Power = V(emf) x Ia = 480 x 20 - 9600W
Speed = P/2 x pi x T = (9600 / 2 x pi x 100) x 60 (to convert to rpm) = 917 rpm
Is this correct?
What do you wish you'd been taught?