The Student Room Group
Reply 1
If it's parallel to the y-axis, then it's of the form x=a, so it has no gradient (or it has an infinite gradient, since you're basically considering gradient=tan(pi/2)). Moreover, if a curve has a tangent that is parallel to the y-axis, then it can't be a graph of a function. (Think "horizontal line test.")
Reply 2
dvs
If it's parallel to the y-axis, then it's of the form x=a, so it has no gradient (or it has an infinite gradient, since you're basically considering gradient=tan(pi/2)). Moreover, if a curve has a tangent that is parallel to the y-axis, then it can't be a graph of a function. (Think "horizontal line test.")

don't you mean vertical line test? besides, what about, say, f(x) = x^1/3 ?
Lol some late reply but it Basically means that Dy/Dx doesn't exist for that point.
Therefore Dy/Dx =f(x)/g(x), say that was your dy/dx g(x)=0 if the a point is parallel to the y axis. also if parallel to the x axis then f(x)=o, dy/dx=0.