This discussion is now closed.
Check out other Related discussions
- How do you pronounce UCAS?
- Help with this chemistry question? (A2, acid-base equilibria)
- chem alevel ocr a question
- aqa acids and bases help :((
- Radiotherapy Elective placement abroad accom reimbursement
- NHS learning support fund
- ............
- Should I change driving instructor and test date??
- KCL confirmation letter hasn’t arrived
- Enrollment KCL?
- OCR A A level Chemistry
- A level Chem help
- Daughter taking year suspension for pregnancy and is there financial support for her
- Switching courses at KCL
- Leaving nursing
- GCSE OCR Business
- kcl 25/26
- Make it More Brewing-ey !!
- My University (KCL) are taking forever to release ratified results!!!
- lab coat diaries 🌸 ⋆｡♡˚💐 [ diary of a year 13 student aspiring to study Pharmacy ⌬🔬 ]
Ka Question
How would do I work this out:
In a 0.150 mol dm-3 solution of weak acid HX at 25C, 1.80% of the acid molecules are dissociated into ions.
Calculate Ka for the acid HX at this temp and state units.
Ka = [H+][X-] / [HX]
... is as far as I've got.
In a 0.150 mol dm-3 solution of weak acid HX at 25C, 1.80% of the acid molecules are dissociated into ions.
Calculate Ka for the acid HX at this temp and state units.
Ka = [H+][X-] / [HX]
... is as far as I've got.
Reply 1
assume that the volume is 1 litre
work out the moles of all components taking intyo account the fact that 1.8% of 0.15 moles of HX have dissociated = 0.0027 moles leaving only 0.1473 moles of acid
Moles of the other two components = 0.0027
sub into equation
work out the moles of all components taking intyo account the fact that 1.8% of 0.15 moles of HX have dissociated = 0.0027 moles leaving only 0.1473 moles of acid
Moles of the other two components = 0.0027
sub into equation
Reply 2
dfghj
OP
Ah thank you 
So,
Ka = [H+]2 / [HX]
= (0.00272) / 0.150
= 4.86 x 10-5
So,
Ka = [H+]2 / [HX]
= (0.00272) / 0.150
= 4.86 x 10-5
Reply 3
wildelectricity
Ah thank you
So,
Ka = [H+]2 / [HX]
= (0.00272) / 0.150
= 4.86 x 10-5
So,
Ka = [H+]2 / [HX]
= (0.00272) / 0.150
= 4.86 x 10-5
Looks like acetic acid
Best,
Borek
--
Related discussions
- How do you pronounce UCAS?
- Help with this chemistry question? (A2, acid-base equilibria)
- chem alevel ocr a question
- aqa acids and bases help :((
- Radiotherapy Elective placement abroad accom reimbursement
- NHS learning support fund
- ............
- Should I change driving instructor and test date??
- KCL confirmation letter hasn’t arrived
- Enrollment KCL?
- OCR A A level Chemistry
- A level Chem help
- Daughter taking year suspension for pregnancy and is there financial support for her
- Switching courses at KCL
- Leaving nursing
- GCSE OCR Business
- kcl 25/26
- Make it More Brewing-ey !!
- My University (KCL) are taking forever to release ratified results!!!
- lab coat diaries 🌸 ⋆｡♡˚💐 [ diary of a year 13 student aspiring to study Pharmacy ⌬🔬 ]
Latest
Trending
Last reply 3 months ago
AQA A level chemistry synthetic routes map - what is the best one to memorise?Last reply 9 months ago
AQA Chemistry Electrode Potentials Conventional Representation QuestionLast reply 10 months ago
OCR B Salters A Level Chemistry 2025 Advanced ArticleLast reply 11 months ago
Help with this chemistry question? (A2, acid-base equilibria)Articles for you
How The Student Room is moderated
To keep The Student Room safe for everyone, we moderate posts that are added to the site.
