I am sort of stuck on this question. (exam- June 2009 question 11 part ii)
The point P on the curve y=kX^0.5 has x-coordinate 4. the normal to the curve p is parallel to the line 2x+3y=0
i) find the value k,
I have found the value k and it is 6
ii) this normal meets the x-axis at the point Q. calculate the area of the triangle OPQ. where o is the point (0,0)
This is the part I am stuck on, I just don't know how to find the co-ordinate of Q.
In the mark scheme the coordinates of Q are (22,0) but i have no idea how they have got this.
Could some one please help me?
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