Advanced Higher Chemistry 2012 Thread

Sorry about how long this has taken me.... Any explanations just ask...

Also please tell me where i went wrong thanks

ADDAB BDCCA CDDBA AACCD CCBDB ACDAB BABDB BCADD

1 a)i) 295.6 ii) 1s2 2s2 2p6 3s2 3p6 3d9
b) Photoconductive/voltaic
c)Positive holes

2a)i)5 ii) 3
b)2HNO2 + 4e- +4H+ ----->>>> H2N2O2 + 2H2O
c) dicyanocuprate(I)

3a) ionic radii
b) 6 chlorine surrounding 1 sodium vice versa
c) KF
d)i) hydration of both ions and lattice enthalpy
ii) Increase in entropy

4a) Trigonal Planar
b) Lone pair of electrons from oxygen donated to form bond, ie only oxygen electrons in bond.
c) ethers

5a) 3.95g
b) Tap water was used which contains metal ions, using deionised would have removed this problem and hence more accurate
c) Copper formed a complex as well as nickel.

6a) Separating Funnel
b)0.13
c) The temperature was different
d) Ethanol is soluble in water due to hydrogen bonding and hence will not partition

7a) 0.575 mol l^-1
b) Hard to see the colour change as the solution is dark brown and hence the equivalence point will be inaccurate
c) CH3COO- (aq)

8a) 500K-> 2000K
b) Since gradient is -entropy, a downwards line represents an increase in entropy.
c)Boiling point of Mg

9)1.45

10) a) 1
B)0
C) s^-1

11)a)i) Hydrogen ii) Hydrogen Chloride
b)i) Acid Chlorides
ii)meh cba
iii) Faster and goes to completion as it is not an equilibrium. Also means greater yield

12a) C8 H14 S2 O2
bi) The one with 3 lines coming out of it
ii) 4 different functional groups and hence asymmetric. Hence Chiral ----> optically active

13a) To make sure that none of the reactants/ products escape on heating
b) Hydrolysis
c) Anti bumping Granules
d) No oily residue remains
e) 3.36g

14a)i) Electrophilic Substitution ii) Phenylamine ( The funny thing is that this question is incorrect as NaOH is required to turn the salt into the phenlyamine but oh well... )
b)i) Check the internet for structure
ii) One double bond no overall charge

15a) Secondary alcohol

b) meh cba

c) Two peaks excluding TMS at 1 and 2 with the peak at 1 having a height of 6 and the peak at 2 having a height of 4.

ah for 4c) wasn't it aldehydes?

I put ketones ... May have been aldehydes though?

the temperature may have been different

It's an ether

dont think 15a is a secondary alcohol because its molecular formula is c4 h9 cl

The empirical formula is always the lowest whole number ratio, the empirical formula for benzene is CH and that isnt a real molocule so i still think the answer was C2H5

How not? A primary would not have worked for the next part of the question because if the OH was at the end no isomers would be formed on dehydrating..

The molecular formula is C4H9Cl

so it must be with either 1-chlorobutane or 2-chlorobutane

There is NO oxygen in the molecular formula, so it can't be any alcohol...

Sorry about how long this has taken me.... Any explanations just ask...

Also please tell me where i went wrong thanks

ADDAB BDCCA CDDBA AACCD CCBDB ACDAB BABDB BCADD

1 a)i) 295.6 ii) 1s2 2s2 2p6 3s2 3p6 3d9
b) Photoconductive/voltaic
c)Positive holes

2a)i)5 ii) 3
b)2HNO2 + 4e- +4H+ ----->>>> H2N2O2 + 2H2O
c) dicyanocuprate(I)

3a) ionic radii
b) 6 chlorine surrounding 1 sodium vice versa
c) KF
d)i) hydration of both ions and lattice enthalpy
ii) Increase in entropy

4a) Trigonal Planar
b) Lone pair of electrons from oxygen donated to form bond, ie only oxygen electrons in bond.
c) ethers

5a) 3.95g
b) Tap water was used which contains metal ions, using deionised would have removed this problem and hence more accurate
c) Copper formed a complex as well as nickel.

6a) Separating Funnel
b)0.13
c) The temperature was different
d) Ethanol is soluble in water due to hydrogen bonding and hence will not partition

7a) 0.575 mol l^-1
b) Hard to see the colour change as the solution is dark brown and hence the equivalence point will be inaccurate
c) CH3COO- (aq)

8a) 500K-> 2000K
b) Since gradient is -entropy, a downwards line represents an increase in entropy.
c)Boiling point of Mg

9)1.45

10) a) 1
B)0
C) s^-1

11)a)i) Hydrogen ii) Hydrogen Chloride
b)i) Acid Chlorides
ii)meh cba
iii) Faster and goes to completion as it is not an equilibrium. Also means greater yield

12a) C8 H14 S2 O2
bi) The one with 3 lines coming out of it
ii) 4 different functional groups and hence asymmetric. Hence Chiral ----> optically active

13a) To make sure that none of the reactants/ products escape on heating
b) Hydrolysis
c) Anti bumping Granules
d) No oily residue remains
e) 3.36g

14a)i) Electrophilic Substitution ii) Phenylamine ( The funny thing is that this question is incorrect as NaOH is required to turn the salt into the phenlyamine but oh well... )
b)i) Check the internet for structure
ii) One double bond no overall charge

15a) Secondary alcohol

b) meh cba

c) Two peaks excluding TMS at 1 and 2 with the peak at 1 having a height of 6 and the peak at 2 having a height of 4.

How not? A primary would not have worked for the next part of the question because if the OH was at the end no isomers would be formed on dehydrating..

This is my first post on TSR so am not sure how this whole thing works but I have the answers my teacher gave me for the multiple choice. He did them pretty quick so there may be a couple mistakes he said.

ADDAB BDCCA CDDBA AACCD CCBDB ACDAB BABDB BDADD

You've given compound B which is a secondary alcohol, it was asking for the structure of A