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# m1 vector question Watch

1. d^2 = 25t^2 - 112t +169

find the length of time to the nearest minute for which the distance is less than 11km
2. (Original post by examweek)
d^2 = 25t^2 - 112t +169

find the length of time to the nearest minute for which the distance is less than 11km
d^2=121

Form a quadratic and factorise .
3. (Original post by examweek)
d^2 = 25t^2 - 112t +169

find the length of time to the nearest minute for which the distance is less than 11km

Now find the critical values by solving,

At the end draw the graph, and find the required length of time.

Updated: May 14, 2012
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