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Mr M's OCR (not OCR MEI) Core 1 answers May 2012

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Reply 380
for question 9i) i finished with x=-7 and x=4 would lose 1 or 2 marks for that?
Reply 381
how many marks will i lose for not wrapping my inequality on q9?
Original post by tazzrudy
for question 9i) i finished with x=-7 and x=4 would lose 1 or 2 marks for that?


3 ...
Reply 383
Original post by Mr M
It was a straightforward paper. That will be a very high mark but you will just have to wait to see your exact UMS.


Hi Mr M, For question 9(i), i did 4x(x+3), then expanded it 4x^2+12x,

but after, instead of having 4x^2+12x<112, i did the rest of the calculations with 4x^2+12x<122, will i get any marks, so from there i rearranged it into a quadratic, and solved it using quadratic formula/Completing the square.

so, will i get any marks?

Thanks.

my answer was a inequality.
(edited 11 years ago)
Reply 384
does anyone have the paper , im resitting, i got a C :frown:
Reply 385
Wouldn't like to resit mechanics as it's the most awkward and difficult to revise for.


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Reply 386
Original post by Rushika
does anyone have the paper , im resitting, i got a C :frown:


Original post by pzoDe
Full question paper:

1. Simplify (x5)(x2+3)(x+4)(x1)(x-5)(x^2+3)-(x+4)(x-1). [3]

2. Express each of the following in the form 7k7^k:
(i) 74\sqrt[4]{7}. [1]
(ii) 177\frac{1}{7\sqrt{7}}. [2]
(iii) 747^4 x 491049^{10}. [2]

3.
(i)
Find the gradient of the line ll which has equation 3x5y20=03x-5y-20=0. [1]
(ii) The line ll crosses the xx-axis at P and the yy-axis at Q. Find the coordinates of the mid-point of PQ. [4]

4.
(i)
Express 2x220x+492x^2-20x+49 in the form p(xq)2+rp(x-q)^2+r. [4]
(ii) State the coordinates of the vertex of the curve y=2x220x+49y=2x^2-20x+49. [2]

5.
(i)
Sketch the curve y=xy=\sqrt{x}. [2]
(ii) Describe the transformation that transforms the curve y=xy=\sqrt{x} to the curve y=x4y=\sqrt{x-4}. [2]
(iii) The curve y=xy=\sqrt{x} is stretched by a scale factor of 5 parallel to the xx-axis. State the equation of the transformed curve. [2]

6. Find the equation of the normal to the curve y=6x25y=\frac{6}{x^2}-5 at the point on the curve where x=2x=2. Give your answer in the form ax+by+c=0ax+by+c=0, where a, b and c are integers. [7]

7. Solve the equation x6x12+2=0x-6x^\frac{1}{2}+2=0, giving your answers in the form p±qrp\pm q\sqrt{r}, where p, q and r are integers. [6]

8.
(i) Find the coordinates of the stationary point on the curve y=x4+32xy=x^4+32x. [5]
(ii) Determine whether this stationary point is a maximum or a minimum. [2]
(iii) For what values of xx does x4+32xx^4+32x increase as xx increases? [1]

9.
(i) A rectangular tile has length 4x4x cm and width (x+3)(x+3) cm. The area of the rectangle is less than 112cm2. By writing down and solving an inequality, determine the set of possible values of xx. [6]
(ii) A second rectangular tile of length 4y4y cm and width (y+3)(y+3) cm has a rectangle of length 2y2y cm and width yy cm removed from one corner as shown in the diagram.

MathsC19ii.png

Given that the perimeter of this tile is between 20cm and 54cm, determine the set of possible values of yy. [5]

10. A circle has equation (x5)2+(y+2)2=25(x-5)^2+(y+2)^2=25.
(i) Find the coordinates of the centre C and the length of the diameter. [3]
(ii) Find the equation of the line which passes through C and the point P (7,2). [4]
(iii) Calculate the length of CP and hence determine whether P lies inside or outside the circle. [3]
(iv) Determine algebraically whether the line with equation y=2xy=2x meets the circle. [5]

Could Mr M copy this to his first post for all to see? Thank you.


Here you go. I do apologise for any mistakes.
Reply 387
Original post by pzoDe
Here you go. I do apologise for any mistakes.

thank youuuuu xxx
What mark was 93 UMS?
Original post by Mr M
Mr M's OCR (not OCR MEI) Core 1 answers May 2012


1. x36x211x^3-6x^2-11 (3 marks)


2. (i) 7147^{\frac{1}{4}} (1 mark)

(ii) 7327^{-\frac{3}{2}} (2 marks)

(iii) 7247^{24} (2 marks)


3. (i) Gradient = 0.6 (1 mark)

(ii) (103,2)(\frac{10}{3}, -2) (4 marks)


4. (i) 2(x5)212(x-5)^2-1 (4 marks)

(ii) (5, -1) (2 marks)


5 (i) Sketch curve (only in first quadrant) (2 marks)

(ii) Translation in positive x direction by 4 units (2 marks)

(iii) y=x5y=\sqrt{\frac{x}{5}} (2 marks)


6. 4x6y29=04x-6y-29=0 (7 marks)


7. 16±6716\pm 6\sqrt7 (6 marks)


8 (i) (-2, -48) (5 marks)

(ii) Minimum (2 marks)

(iii) x2x \geq -2 (x > -2 will be marked right) (1 mark)


9 (i) 0<x<40<x<4 (6 marks)

(ii) 1.4y4.81.4 \leq y \leq 4.8 (5 marks)


10 (i) Centre (5, -2) Diameter 10 (3 marks)

(ii) y = 2x - 12 (4 marks)

(iii) 252 \sqrt 5 and inside (3 marks)

(iv) No (5 marks)


Hey i was wondering whether you could go through Q10, I'm having some difficulty with it and can't find any solutions online, especially part ii). Thank you
Original post by Aspiringacc
Hey i was wondering whether you could go through Q10, I'm having some difficulty with it and can't find any solutions online, especially part ii). Thank you


I can't remember this far back! Ask your teacher tomorrow?
Original post by Mr M
I can't remember this far back! Ask your teacher tomorrow?


I want to but I've got a test tommorow and I only just found this past paper online.. I was just wondering, how could you find the equation? because I just worked out the gradient of C and P, but from then on I just got it wrong..

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