# AQA GCSE C3 Chemistry Titration Calculations

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#1
Hi, I'm struggling with the titration calculations in AQA C3 GCSE. A way of remembering the method and some more information on how to do them would be much appreciated. Thanks
0
7 years ago
#2
(Original post by zacaroniandcheese)
Hi, I'm struggling with the titration calculations in AQA C3 GCSE. A way of remembering the method and some more information on how to do them would be much appreciated. Thanks
The easiest way to get a hang of titration calculations is to do as many as possible.

Post up a few questions if you're having problems in specific areas.
0
7 years ago
#3
Ok then...

So say:

35cm3 of Hydrochloric Acid reacts with 27.5cm3, 0.3mol/dm3 NaOH. What is the Concentration of the Hydrochloric Acid:

1. Write out what you know:

HCL - VOL: 35 --- CONC: (x) --- MOL: (x)
NaOH - VOL: 27.5 --- CONC: 0.3 --- MOL: (x)

2. Realise what you can work out - Mol of NaOH in this case
Mol = Conc x (Vol/1000)
so Mol = 0.3 x (27.5/1000)
Mol = 0.00825

3. Now you have all the Info for one substance and most importantly the moles of a substance.

4. Mol Ratio is 1:1 unless the question says otherwise

5. Rearrange Mol = Conc x (Vol/1000)
to make Conc = Mol / (Vol/1000)
Conc = 0.00825 / (35/1000)
Conc = 0.235

0.24mol/dm3 = Conc of HCL

Hope I helped
4
#4
Thank you Definitely getting the hang of it.
0
1 year ago
#5
(Original post by steviep14)
Ok then...

So say:

35cm3 of Hydrochloric Acid reacts with 27.5cm3, 0.3mol/dm3 NaOH. What is the Concentration of the Hydrochloric Acid:

1. Write out what you know:

HCL - VOL: 35 --- CONC: (x) --- MOL: (x)
NaOH - VOL: 27.5 --- CONC: 0.3 --- MOL: (x)

2. Realise what you can work out - Mol of NaOH in this case
Mol = Conc x (Vol/1000)
so Mol = 0.3 x (27.5/1000)
Mol = 0.00825

3. Now you have all the Info for one substance and most importantly the moles of a substance.

4. Mol Ratio is 1:1 unless the question says otherwise

5. Rearrange Mol = Conc x (Vol/1000)
to make Conc = Mol / (Vol/1000)
Conc = 0.00825 / (35/1000)
Conc = 0.235

0.24mol/dm3 = Conc of HCL

Hope I helped
I have a chemistry test tomorrow and this just saved my life. Thank you so much.
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