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# did anyone do ccea maths c1 today Watch

1. i got everthing right apart from maybe question 8, i got
- 4 - (2 root 2) < X < - 4 + (2 root 2). is that right
2. Yea i did it today! cant remember what i got but it was something like that!
3. What answers did use get in each question? What did use think of the paper overall?
4. Hi yeah I did it,
I got something similar to that answer for question 8 as well. What did you get for question 7?
5. (Original post by Pyro2000x)
i got everthing right apart from maybe question 8, i got
- 4 - (2 root 2) < X < - 4 + (2 root 2). is that right
This is right.
6. (Original post by Alfie1993)
Hi yeah I did it,
I got something similar to that answer for question 8 as well. What did you get for question 7?
what was it about, we had to give up our question book
7. (Original post by Pyro2000x)
what was it about, we had to give up our question book
The cost function which you had to say was increasing when t>2
8. Here are my answers can anyone give any feedback?
1. Simplifying an equation - 5
b) graph functions, f(x-1) moved one to the right
f(-x) reflected in the y axis
2. x=20 y=45 z=30
3a)i) gradient of AB = 2
ii) equation of line perpendic to AB going through (-1,1)
2y=-x-1
b) differentiating y=4x^3 - x^-1/3
i got - 12x^2 + 1/3x^-4/3
4. curve and line meeting at points C and D
i) find co ordinates - C (2,-1) D (4,3)
ii) exact length - sq root of 20/ 2root 5
5a) factor theorem ii) factories fully - (2x-1)(x+2)(x+1)
iii)solve equation so x=1/2, x=-2, x=-1
b) triangle q
6root 3 + 4
couldn't do i)
ii) 17/2
7a)i) dy/dx of x^4 + 32x
4x^3 + 32
ii) find x co ord of turning point and its nature
x= -2, minimum
b) cost
t > cube root of 6 ( i know thats wrong)
8. curves that didn't meet
i got the discriminant to be m^2 + 8m + 8<0 and instead of using the quad formula i did m^2 + 8m < - 8
and ended up with like -8<m<-16 or something stupid

anyone get any of the same answers?
9. (Original post by B18)
Here are my answers can anyone give any feedback?
1. Simplifying an equation - 5
b) graph functions, f(x-1) moved one to the right
f(-x) reflected in the y axis
2. x=20 y=45 z=30
3a)i) gradient of AB = 2
ii) equation of line perpendic to AB going through (-1,1)
2y=-x-1
b) differentiating y=4x^3 - x^-1/3
i got - 12x^2 + 1/3x^-4/3
4. curve and line meeting at points C and D
i) find co ordinates - C (2,-1) D (4,3)
ii) exact length - sq root of 20/ 2root 5
5a) factor theorem ii) factories fully - (2x-1)(x+2)(x+1)
iii)solve equation so x=1/2, x=-2, x=-1
b) triangle q
6root 3 + 4
couldn't do i)
ii) 17/2
7a)i) dy/dx of x^4 + 32x
4x^3 + 32
ii) find x co ord of turning point and its nature
x= -2, minimum
b) cost
t > cube root of 6 ( i know thats wrong)
8. curves that didn't meet
i got the discriminant to be m^2 + 8m + 8<0 and instead of using the quad formula i did m^2 + 8m < - 8
and ended up with like -8<m<-16 or something stupid

anyone get any of the same answers?

The cube root of 6 was wrong, it was supposed to be t>2. Number 8, you did wrong, but you would have gained some marks for getting as far as the quadratic inequality. I think your factorising in the long division may be wrong. Also, the equation of the perpendicular line; I think you may have got a sign or two wrong. Apart from that, all good
10. unreal i am almost certain i got 100%
11. How did you think you had 100% when you didnt even attempt 6)i.
Sorry to sound harsh!
12. It was a decent paper. I messed up in a few spots but I think I'll get a high B/ an A.
13. (Original post by acrawford957)
How did you think you had 100% when you didnt even attempt 6)i.
Sorry to sound harsh!
It wasn't him who said that.

(Original post by xDanny 117)
It was a decent paper. I messed up in a few spots but I think I'll get a high B/ an A.
What did you mess up on?
14. (Original post by acrawford957)
How did you think you had 100% when you didnt even attempt 6)i.
Sorry to sound harsh!
that is not me
15. (Original post by acrawford957)
How did you think you had 100% when you didnt even attempt 6)i.
Sorry to sound harsh!
lol yeah... i never said i thought i got 100% that was someone else
16. (Original post by CD315)
The cube root of 6 was wrong, it was supposed to be t>2. Number 8, you did wrong, but you would have gained some marks for getting as far as the quadratic inequality. I think your factorising in the long division may be wrong. Also, the equation of the perpendicular line; I think you may have got a sign or two wrong. Apart from that, all good
would you talk me through 6i) 7b) and 8? also what was the perpendicular equation meant to be?
17. (Original post by CD315)

What did you mess up on?
Used the wrong 'length of a line' formula in a question, couldn't get a final value for when the cost is increasing in Q7, only got to the quadratic inequality in Q8.
18. (Original post by B18)
would you talk me through 6i) 7b) and 8? also what was the perpendicular equation meant to be?
You had a negative 1 which I think was supposed to be a positive.

6i; wasn't this the speed one? You just had something along the lines of 17/x + 13/(x-2) if I remember correctly? Then just add them and set equal to 4. (They're the expressions for time taken.)

7b; you differentiated the function and said it was greater than 0. You ended up with it being 2.

8; set the curves equal to each other and you'll form a quadratic. Since there is no solutions to this, due to them not meeting, you take the discriminant and say it's less than 0. I ended up with a quadratic inequality which I then drew a graph of.

Updated: May 24, 2012
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