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    When calculating activation energy am i right in thinking that it is calculated by multiplying the gradient of the straight line on the graph (when plotting lnk against 1/T) by the gas constant (8.31 JK-1)? and if so what are the units of the activation energy? thanku xxx
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    (Original post by devilschild)
    When calculating activation energy am i right in thinking that it is calculated by multiplying the gradient of the straight line on the graph (when plotting lnk against 1/T) by the gas constant (8.31 JK-1)? and if so what are the units of the activation energy? thanku xxx
    Activation energy = gradient x -8.31

    units = J mol^-1 K^-1
 
 
 
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