This discussion is now closed.

Check out other Related discussions

- Analytical analysis
- A level tips
- Getting ahead in Year 10!
- Please Mark My Essay - GCSE English Lit
- How do I learn how to use tools?
- Keeping completed worksheets and questions for science and maths? Gcse
- Need help on maths foundation question Gcse
- How do I revise?
- How to ground Anti-Static Wrist Strap?
- Changing course at the same university?
- IPO
- Igcse chem revision help
- my boyfriend failed his gcse
- IGCSE's Leaked?
- Help to elevate my gsce English lang story
- Physics question resultant forces
- Vertical motion SUVAT equations
- A level Physics Help
- Mechanics help
- east park ground floor

I'm really struggling with the last part of this question:

A hammer of mass 100kg falls 4 metres onto a pile of mass 300kg and drives it 80mm into the ground.

a) Calculate the loss of energy on impact

b) Calculate the work done by the resistance of the ground

c) Calculate the average resistance to penetration

Please help!

A hammer of mass 100kg falls 4 metres onto a pile of mass 300kg and drives it 80mm into the ground.

a) Calculate the loss of energy on impact

b) Calculate the work done by the resistance of the ground

c) Calculate the average resistance to penetration

Please help!

The falling mass sees a decrease in it KE. It has max PE at the top.

Can you determine the energy loss ?

This was posted from The Student Room's Android App on my GT-I9100

Can you determine the energy loss ?

This was posted from The Student Room's Android App on my GT-I9100

Interesting question and I would like to see the actual answer, do you happen to have it?

I spent a good while looking at it and this is what I did:

a) Calculate the loss of energy on impact

GPE is 100*9.81*4 = 3924J

Kinetic energy just before contact is therefore 3924J also.

From this velocity can be found to be 8.86m/s

From the conservation of momentum, initial momentum = 100*8.86 = 886Ns = final momentum = (100+300)*V

The final velocity is therefore 2.2m/s

The final Kinetic energy is 1/2 * 400* 2.2^2 = 986J

The energy that is lost is therefore 3924 - 986 = 2938J

b) Calculate the work done by the resistance of the ground

Kinetic energy + GPE = Work done by resistance

986 (worked out in part a) + 400*9.81*0.08 (height lost as pile penetrates ground) = 1300J

c) Calculate the average resistance to penetration

Work done =FS

1300/0.08 = 16250N

Hope at least some of that helps, im not too confident in my answers but thought I'd give it a go! If you find the correct answers please let me know!

I spent a good while looking at it and this is what I did:

a) Calculate the loss of energy on impact

GPE is 100*9.81*4 = 3924J

Kinetic energy just before contact is therefore 3924J also.

From this velocity can be found to be 8.86m/s

From the conservation of momentum, initial momentum = 100*8.86 = 886Ns = final momentum = (100+300)*V

The final velocity is therefore 2.2m/s

The final Kinetic energy is 1/2 * 400* 2.2^2 = 986J

The energy that is lost is therefore 3924 - 986 = 2938J

b) Calculate the work done by the resistance of the ground

Kinetic energy + GPE = Work done by resistance

986 (worked out in part a) + 400*9.81*0.08 (height lost as pile penetrates ground) = 1300J

c) Calculate the average resistance to penetration

Work done =FS

1300/0.08 = 16250N

Hope at least some of that helps, im not too confident in my answers but thought I'd give it a go! If you find the correct answers please let me know!

Where the hell did you get 2.2 m/s as the final velocity?

Original post by rub em out

Interesting question and I would like to see the actual answer, do you happen to have it?

I spent a good while looking at it and this is what I did:

a) Calculate the loss of energy on impact

GPE is 100*9.81*4 = 3924J

Kinetic energy just before contact is therefore 3924J also.

From this velocity can be found to be 8.86m/s

From the conservation of momentum, initial momentum = 100*8.86 = 886Ns = final momentum = (100+300)*V

The final velocity is therefore 2.2m/s

The final Kinetic energy is 1/2 * 400* 2.2^2 = 986J

The energy that is lost is therefore 3924 - 986 = 2938J

b) Calculate the work done by the resistance of the ground

Kinetic energy + GPE = Work done by resistance

986 (worked out in part a) + 400*9.81*0.08 (height lost as pile penetrates ground) = 1300J

c) Calculate the average resistance to penetration

Work done =FS

1300/0.08 = 16250N

Hope at least some of that helps, im not too confident in my answers but thought I'd give it a go! If you find the correct answers please let me know!

I spent a good while looking at it and this is what I did:

a) Calculate the loss of energy on impact

GPE is 100*9.81*4 = 3924J

Kinetic energy just before contact is therefore 3924J also.

From this velocity can be found to be 8.86m/s

From the conservation of momentum, initial momentum = 100*8.86 = 886Ns = final momentum = (100+300)*V

The final velocity is therefore 2.2m/s

The final Kinetic energy is 1/2 * 400* 2.2^2 = 986J

The energy that is lost is therefore 3924 - 986 = 2938J

b) Calculate the work done by the resistance of the ground

Kinetic energy + GPE = Work done by resistance

986 (worked out in part a) + 400*9.81*0.08 (height lost as pile penetrates ground) = 1300J

c) Calculate the average resistance to penetration

Work done =FS

1300/0.08 = 16250N

Hope at least some of that helps, im not too confident in my answers but thought I'd give it a go! If you find the correct answers please let me know!

Are you sure for the answer on c?

- Analytical analysis
- A level tips
- Getting ahead in Year 10!
- Please Mark My Essay - GCSE English Lit
- How do I learn how to use tools?
- Keeping completed worksheets and questions for science and maths? Gcse
- Need help on maths foundation question Gcse
- How do I revise?
- How to ground Anti-Static Wrist Strap?
- Changing course at the same university?
- IPO
- Igcse chem revision help
- my boyfriend failed his gcse
- IGCSE's Leaked?
- Help to elevate my gsce English lang story
- Physics question resultant forces
- Vertical motion SUVAT equations
- A level Physics Help
- Mechanics help
- east park ground floor

Last reply 1 minute ago

Official Lancaster University Offer Holders Thread for 2024 entryLast reply 1 minute ago

Does applying for higher maintenance loan delay tuition fees if complications happenLast reply 4 minutes ago

Im confused about this chemistry question, why does it form these productsLast reply 5 minutes ago

Amazon Project management apprenticeship 2024Last reply 8 minutes ago

BA (hons) Philosophy at University of London/OU student finance queryLast reply 8 minutes ago

Official Veterinary Medicine Applicants thread 2024 entryLast reply 13 minutes ago

Official Politics and/or International Relations Applicants Thread 2024Last reply 15 minutes ago

English but permanently moving to Wales for studyLast reply 16 minutes ago

CPS Pupillage/Legal Trainee Scheme 2024 (2025 Start)Last reply 17 minutes ago

Teaching jobs with visa sponsorship as a non-UK citizenLast reply 17 minutes ago

Accounting a level or apprenticeshipLast reply 18 minutes ago

Is Nursing MSc Exempt from second Masters fundingPosted 18 minutes ago

Physiotherapy (B160) - Ulster UniversityLast reply 19 minutes ago

For harrasment does someone get a warning first or no warningLast reply 19 minutes ago

OCR A-Level Biology A Paper 1 (H420/01) - 5th June 2024 [Exam Chat]