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# Simultaneous equations watch

1. (x+y)^2 = 4
2y - x = 0

what do you get?
2. (Original post by mik1a)
(x+y)^2 = 4
2y - x = 0

what do you get?
2y-x = 0 => x=2y

So, (3y)^2 = 4

9y^2 = 4

y^2 = 4/9

y = 2/3 or y = -2/3

y=2/3, x=4/3

y=-2/3, x=-4/3
3. (Original post by mik1a)
(x+y)^2 = 4
2y - x = 0

what do you get?
basically to make those easy, you just have to rearrange and subsititue in for x or y
4. that seems really obvious now thanks... i did it some other way and got 1/3, -1/3 2/3, -2/3 :s got to make less errors...
5. (Original post by mik1a)
that seems really obvious now thanks... i did it some other way and got 1/3, -1/3 2/3, -2/3 :s got to make less errors...
fewer errors not less :-)
6. lol rub it in

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