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    (x+y)^2 = 4
    2y - x = 0

    what do you get?
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    (Original post by mik1a)
    (x+y)^2 = 4
    2y - x = 0

    what do you get?
    2y-x = 0 => x=2y

    So, (3y)^2 = 4

    9y^2 = 4

    y^2 = 4/9

    y = 2/3 or y = -2/3

    y=2/3, x=4/3

    y=-2/3, x=-4/3
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    (Original post by mik1a)
    (x+y)^2 = 4
    2y - x = 0

    what do you get?
    basically to make those easy, you just have to rearrange and subsititue in for x or y
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    that seems really obvious now thanks... i did it some other way and got 1/3, -1/3 2/3, -2/3 :s got to make less errors...
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    (Original post by mik1a)
    that seems really obvious now thanks... i did it some other way and got 1/3, -1/3 2/3, -2/3 :s got to make less errors...
    fewer errors not less :-)
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    lol rub it in
 
 
 

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