The Student Room Group

Reply 1


Volume of O2 used=100-35=65
Volume of CO2 released=75-35=40
Therfore the mole ratio w.r.t Hydrocarbon:
O2:CO2:CxHy
6.5:4:1
Using the equation:
CxHy+(x+y/4)O2---->(x)CO2+(y/2)H2O

using the ratios x=4
x+y/4=6.5
4+y/4=6.5
y=10
The formula of compound C4H10

How The Student Room is moderated

To keep The Student Room safe for everyone, we moderate posts that are added to the site.