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lalibacha
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Report Thread starter 17 years ago
#1
can someone plese help me do this problem...

Calculate the energy change for the formation of 1.19 mol of NaBr(s) given the following information.

Since Br2is a liquid at room temperature, it requires one more step than is in your text. That step is given here.

Br2(l) --> Br2(g) : 30.92 KJ/mol

Na(s) --> Na(g) : 107.32 KJ/mol

2Br(g) --> Br2(g) : -254.66 KJ/mol

Na(g) --> Na+(g) + e- : 496 KJ/mol

Br(g) + e- --> Br-(g) : -324.7 KJ/mol

Lattice energy for NaBr = -752 KJ/mol

i would appreciate it greatly!!!
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FunkMaster
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#2
Report 17 years ago
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