Need help with further differentiation please! Watch

Tynos
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#1
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\frac{4x}{x^3} - \frac{3x^1/2}{x^3}

First time using latex, anyway please help.
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Tynos
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#2
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\displaystyle \frac{4x}{\partial x} x^2y = 2xy
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usycool1
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#3
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(Original post by Tynos)
\frac{4x}{x^3} - \frac{3x^1/2}{x^3}

First time using latex, anyway please help.
Write it in the form:

4x^p-3x^q where you have to find p and q.

After doing so, differentiate.

Hint:

\frac{4}{x}=4x^{-1}
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Tynos
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#4
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I know lol, im stuck at the second part.
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Unkempt_One
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Hi, I don't know how to use the Math Editor so bear with me.
d/dx(x^p)=p*x^(p-1) provided p =/= 0
It's a fairly simple rule, the derivation is quite straightforward if you know binomial expansions.
If you use that with the hints above you can get an answer.
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Tynos
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#6
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Im just stuck on this part \frac{3x^1/2}{x^3}
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TenOfThem
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#7
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(Original post by Tynos)
Im just stuck on this part \frac{3x^1/2}{x^3}
\frac{1}{2} - 3 = -\frac{5}{2}

so

\dfrac{3x^{\frac{1}{2}}}{x^3} = 3x^{-\frac{5}{2}}
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