The Student Room Group

Scroll to see replies

Original post by justinawe
Surely 15 GCSEs >
9 IGCSEs in terms of workload, though?


IGCSEs are harder in a way but they don't have coursework.
Original post by L'Evil Fish
Maybe... 15 GCSEs + Welsh Baccalaureate (worth 3/4 GCSEs) probably is :tongue:

But I have some useless GCSEs:
Art
Photography
Media
Business
Welsh

My Username is really Poisson Distribution :mmm:


How good is your Welsh? :redface:
Original post by justinawe
How good is your Welsh?


:erm: my French is much better... :yy:

Welsh is terrible... :colonhash: probably get an A/B... If I'm lucky!

My Username is really Poisson Distribution :mmm:
Original post by Abject Testament
IGCSEs are harder in a way but they don't have coursework.


Yes, that's the good part. For me, anyway.
Original post by justinawe
Yes, that's the good part. For me, anyway.


I love coursework though :tongue: for science anyway :biggrin:

My Username is really Poisson Distribution :mmm:
Original post by L'Evil Fish
Does that say kx^2 if so:

f'(x) is: 2kx

My Username is really Poisson Distribution :mmm:


Yeah it did lol. Is there a generic way of finding the answer?

My Username is really Poisson Distribution :mmm:
Original post by cheetahs56
Yeah it did lol. Is there a generic way of finding the answer?

My Username is really Poisson Distribution :mmm:


Yes :smile:

y = ax^n
dy/dx = (n)ax^(n-1)

Eg y = 5x^3
dy/dx = (3)5x^(3-1) = 15x^2

y = ax
dy/dx = a

Eg y = 6x
dy/dx = 6

y = a
dy/dx = 0

My Username is really Poisson Distribution :mmm:
Original post by justinawe
Yes, that's the
good part. For me, anyway.


Same :tongue:
Original post by L'Evil Fish
Yes :smile:

y = ax^n
dy/dx = (n)ax^(n-1)

Eg y = 5x^3
dy/dx = (3)5x^(3-1) = 15x^2

y = ax
dy/dx = a

Eg y = 6x
dy/dx = 6

y = a
dy/dx = 0

My Username is really Poisson Distribution :mmm:


:yes: C1?


This was posted from The Student Room's iPhone/iPad App
Original post by cheetahs56
Yeah it did lol. Is there a generic way of finding the answer?

My Username is really Poisson Distribution :mmm:


The normal way?

d(kx2)dx\frac{d(kx^2)}{dx}

=2(kx21)= 2(kx^{2-1})

=2kx= 2kx

If the constant is multiplied with a variable (i.e. x), you just leave it there when differentiating.
Original post by This Honest
:yes: C1?


This was posted from The Student Room's iPhone/iPad App


Yeah, cheetah wanted the generic way :tongue: so I gave it :yep:

My Username is really Poisson Distribution :mmm:
Original post by L'Evil Fish
Yes :smile:

y = ax^n
dy/dx = (n)ax^(n-1)

Eg y = 5x^3
dy/dx = (3)5x^(3-1) = 15x^2

y = ax
dy/dx = a

Eg y = 6x
dy/dx = 6

y = a
dy/dx = 0

My Username is really Poisson Distribution :mmm:


Lol, is that all it was? I knew the dy/dx rule already :tongue:

*sigh*, the humiliation when a year 11 is helping you with your Maths work. :colondollar:

And yep, C1 :biggrin:

My Username is really Poisson Distribution :mmm:
Original post by cheetahs56
Lol, is that all it was? I knew the dy/dx rule already :tongue:

*sigh*, the humiliation when a year 11 is helping you with your Maths work. :colondollar:

And yep, C1 :biggrin:

My Username is really Poisson Distribution :mmm:


:rofl: don't worry, he's one of a kind :wink:
Really? Humiliation? That's a bit strongly worded.
Original post by cheetahs56
Lol, is that all it was? I knew the dy/dx rule already :tongue:

*sigh*, the humiliation when a year 11 is helping you with your Maths work. :colondollar:

And yep, C1 :biggrin:

My Username is really Poisson Distribution :mmm:


:yep: that's all it is :tongue:

It's not humiliating :sigh:

:woo:

My Username is really Poisson Distribution :mmm:
Original post by Abject Testament
Same :tongue:


Did you do IGCSEs as well?
Mixture of IGCSEs and normal gcses
Just in awe, can you check this, volume of revolution, of y = x + 3/Rootx between 1 and 4.

Spoiler



Is that right so far?

My Username is really Poisson Distribution :mmm:
(edited 11 years ago)
Original post by L'Evil Fish
Just in awe, can you check this, volume of revolution, of y = x + 3/Rootx between 1 and 4.

y = x + 3/Rootx between 1 and 4.

Pi *integral* y^2 dx
Pi *integral* (x^2 + 6x/Rootx + 9/x) dx
Pi *integral* (x^2 + 6x(x^-1/2) + 9(x^-1)) dx
Pi [x^3/3 + 3/Rootx -9/x^2]
Pi [(64/3 + 3/2 - 9/16)-(1/3 + 3 - 9)]
Pi (1053/48+ 272/48)
Pi (1325/48)
1325Pi/48

Excuse lack of latex...


Is that right so far?

My Username is really Poisson Distribution :mmm:


Not quite sure how you got this... think you integrated it wrong.
Original post by justinawe
Not quite sure how you got this... think you integrated it wrong.


:facepalm:

I differentiated the second bits randomly xD

Re check the edit?

My Username is really Poisson Distribution :mmm:
(edited 11 years ago)

Latest