Maths Anyone :(Watch
I was given this exmaple from my teacher:
sqrt of 12 = 2 sqrt 3
Using this example I had to do the same for 32.
I got 2 sqrt 2.
I've never done surds before, any pointers?
I appreciate any help, I think I'm a lost cause when it comes to surds!
i would suggest expressing 32 as a product of it's factors
ie 32 = (2x2x2x2x2) = [(2^2)x(2^2)x2]
now root 32 = root [(2^2)x(2^2)x2] = root (2^2) x root (2^2) x root 2
this equals 2 x 2 x root 2 which is 4 root 2
Hope this helps, if not i'll happily explain further if needed
I can only go so far with the sums and then it just falls apart!
Thank you for helping
sqroot 32 is the same as sqroot 2 x 16
When you have a multiplaction in a sqroot (eg sqroot 2 x 16) you can sqroot one of the terms and bring the result outside the sqroot, therefore
=sqroot 16 x 2
=4 sqroot 2
Hope this helps
Talk about simplifying an issue!!
That really helped, thanks for the explination!
I had surds down to a fine art until I came across trying to work out 89.
How do you work out odd numbers?
Sorry about this