# Maths Anyone :(

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#1
Hi All!

Surds

I was given this exmaple from my teacher:

sqrt of 12 = 2 sqrt 3

Using this example I had to do the same for 32.

I got 2 sqrt 2.

I've never done surds before, any pointers?

I appreciate any help, I think I'm a lost cause when it comes to surds!
0
17 years ago
#2
hi

i would suggest expressing 32 as a product of it's factors

ie 32 = (2x2x2x2x2) = [(2^2)x(2^2)x2]

now root 32 = root [(2^2)x(2^2)x2] = root (2^2) x root (2^2) x root 2

this equals 2 x 2 x root 2 which is 4 root 2

Hope this helps, if not i'll happily explain further if needed
0
#3
I'd love some more of an explination - thanks!

I can only go so far with the sums and then it just falls apart!

Thank you for helping
0
17 years ago
#4
Basically it goes like this

sqroot 32 is the same as sqroot 2 x 16

When you have a multiplaction in a sqroot (eg sqroot 2 x 16) you can sqroot one of the terms and bring the result outside the sqroot, therefore

=sqroot 32
=sqroot 16 x 2
=4 sqroot 2

Hope this helps
0
#5
Thanks you so much for that!

That really helped, thanks for the explination!

Lissy
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#6
Okay then,
I had surds down to a fine art until I came across trying to work out 89.

How do you work out odd numbers?

0
17 years ago
#7
Well the problem with simplifying sqrt of 89 isn't that it's odd but because it's a prime number. Therefore it cannot be simplified.
0
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