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# c1 - circles watch

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1. Im looking at a past paper...
Came accross a question, not sure how to do it..

Ive already done a and b, so i edited the image.

Thanks

2. Were's the question?
3. Can you not see the image?! :s
4. (Original post by magnum)
Can you not see the image?! :s
No?
5. Ah nevermind, non-subs can't post images, so they aren't being diplayed. I'll post it for you:

6. Thankyou.
7. ci) sub y+x+4 into equation x^2+y^2-12x-6y+20=0
gives: x^2 + (x+4)^2 -12x -6(x+4) +20=0
sort out to give: 2x^2-10x+12=0
Divide this by 2 to give: x^2 -5x +6=0
cii) Factorise to give: (x-3)(x-2)
so x=3 or x=2
Next find y coordinates of p + q:
Using y=x+4
y=3+4
y=7
so p= (3,7)
y=2+4
y=6
so q =(2,6)

Hope that helps.
8. Thankyou, much appreciated
9. (Original post by magnum)
Thankyou, much appreciated

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