integration by parts Watch

phillie
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#1
Report Thread starter 12 years ago
#1
how do you integrate

x(secx)^2

?
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Christophicus
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#2
Report 12 years ago
#2
(Original post by phillie)
how do you integrate

x(secx)^2

?
Let u = x, dv/dx = (secx)^2
Then integrate by parts.
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Nima
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#3
Report 12 years ago
#3
(Original post by phillie)
how do you integrate

x(secx)^2

?
Int. x.sec^2x dx
Let u = x => du/dx = 1
Let dv/dx = sec^2x => v = tanx
:. Int. x.sec^2x dx = xtanx - Int. tanx dx = xtanx - ln|secx| + k
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