The Student Room Group

Complex Numbers

verify 3+i is the root of the equation z^2-(2+4i)z+8i-6=0 how do you do this ive never seen this :biggrin:
Reply 1
put 3+i where z is and show it =0
z = x+iy

so, perhaps, sub it into the equation given?
Reply 3
Let f(z)=z^2-(2+4i)z+8i-6 and then show f(3+i)=0.

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