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    Could someone solve this Statistics Question for me:

    A market sells potatoes weighing more than 80 grams packed seperately packaged. Potatoes weighing between 80 and L grams are labelled as 'large', while potaotoes over L grams are labelled as 'extra large'.
    Given that a randomly chosen potato is twice as likely to be 'large' as 'extra large', calculate the value of L.

    Given data: Mean: 65 grams, Standard Deviation: 15 grams.
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    (Original post by aiman)
    Could someone solve this Statistics Question for me:

    A market sells potatoes weighing more than 80 grams packed seperately packaged. Potatoes weighing between 80 and L grams are labelled as 'large', while potaotoes over L grams are labelled as 'extra large'.
    Given that a randomly chosen potato is twice as likely to be 'large' as 'extra large', calculate the value of L.

    Given data: Mean: 65 grams, Standard Deviation: 15 grams.
    80<X<L = large
    X>L = extra large

    P(X>80)
    = P(Z>[80-65]/15)
    = P(Z>1)
    = 0.1587

    Since a randomly chosen potato is twice as likely to be "large" as "extra large"
    P(X>L) = 1/3 * (0.1587)
    P(Z>[L-65]/15) = 0.0529
    P(Z<[L-65]/15) = 0.9471
    (L-65)/15 = 1.618
    L = 89.3 (3 s.f.)
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    Thanks alot
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    (Original post by aiman)
    Thanks alot
    You're welcome.
 
 
 
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Updated: April 10, 2006
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