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Simple Trig
Hi
Given that 2sin2x=cos2x,
(a) show that tan2x=0.5 (done this part)
(b) Hence find the values of X, to one decimal place, in the interval
0<or equal x<360 (DOESN'T INCLUDE 360) for which
2sin2x=cos2x
Is x=13.3 (1dp) a solution?
help!
Given that 2sin2x=cos2x,
(a) show that tan2x=0.5 (done this part)
(b) Hence find the values of X, to one decimal place, in the interval
0<or equal x<360 (DOESN'T INCLUDE 360) for which
2sin2x=cos2x
Is x=13.3 (1dp) a solution?
help!
Yes 13.3 degrees is a solution...
we have tan2x = 0.5
2x = arctan (0.5)
so 2x = 26.6, 206.6, 386.6, 566.6 (all to 1 dp)
so x = 13.3, 103.3, 193.3, 283.3 (all to 1 dp)
we have tan2x = 0.5
2x = arctan (0.5)
so 2x = 26.6, 206.6, 386.6, 566.6 (all to 1 dp)
so x = 13.3, 103.3, 193.3, 283.3 (all to 1 dp)
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