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# Simple Trig watch

1. Hi

Given that 2sin2x=cos2x,

(a) show that tan2x=0.5 (done this part)

(b) Hence find the values of X, to one decimal place, in the interval

0<or equal x<360 (DOESN'T INCLUDE 360) for which

2sin2x=cos2x

Is x=13.3 (1dp) a solution?

help!
2. Yes 13.3 degrees is a solution...

we have tan2x = 0.5

2x = arctan (0.5)

so 2x = 26.6, 206.6, 386.6, 566.6 (all to 1 dp)

so x = 13.3, 103.3, 193.3, 283.3 (all to 1 dp)

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