Hello, I thought I make a thread on this because I keep getting stuck on little things while Im revising and Im sure you lot know the answers.
How do you integrate: [x[(x^2)-3]^0.5]^2
Thanks
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Boss_Capone
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- 10-04-2006 19:39
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the_anomaly
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- 10-04-2006 19:52
(x(x^2-3)^0.5)^2 = x^2(x^2 - 3) = x^4 - 3x^2....this is now standard integration
hope this helps -
driving_seat
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- 10-04-2006 19:53
[x[(x^2)-3]^0.5]^2
[x[(x^2)-3]^1
[x[(x^2)-3]
x^3-3x
integrate have fun -
the_anomaly
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- 10-04-2006 20:00
(Original post by driving_seat)
[x[(x^2)-3]^1 -
Christophicus
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- 10-04-2006 20:01
(Original post by driving_seat)
[x[(x^2)-3]^0.5]^2
[x[(x^2)-3]^1
[x[(x^2)-3]
x^3-3x
integrate have fun -
Boss_Capone
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- 10-04-2006 20:58
thanks alot people
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Boss_Capone
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- 11-04-2006 09:57
Differentiate: [x[(x^2)-3]^0.5]
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- 11-04-2006 10:31
(x^2)(x^2-3)^-1/2
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