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    Hello, I thought I make a thread on this because I keep getting stuck on little things while Im revising and Im sure you lot know the answers.

    How do you integrate: [x[(x^2)-3]^0.5]^2

    Thanks
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    (x(x^2-3)^0.5)^2 = x^2(x^2 - 3) = x^4 - 3x^2....this is now standard integration

    hope this helps
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    [x[(x^2)-3]^0.5]^2
    [x[(x^2)-3]^1
    [x[(x^2)-3]
    x^3-3x
    integrate have fun
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    (Original post by driving_seat)
    [x[(x^2)-3]^1
    have u not forgot to square the first x in this line....
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    (Original post by driving_seat)
    [x[(x^2)-3]^0.5]^2
    [x[(x^2)-3]^1
    [x[(x^2)-3]
    x^3-3x
    integrate have fun
    wrong!
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    thanks alot people
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    Differentiate: [x[(x^2)-3]^0.5]
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    (x^2)(x^2-3)^-1/2
 
 
 
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Updated: April 11, 2006
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