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    Q/[W(Q-W)], Looking at it straight away I spot the answer is:
    1/W + 1/(Q-W)

    But when I went through the usual steps for finiding partial practions it just didn't work:confused: .
    You know, the:

    Q/[W(Q-W)] = A/W + B/(Q-W), :. Q = A(Q-W) + BW

    Then I wrote a page of rubbish which didn't lead to the correct answer....
    Anyone care to show me their workings out?
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    Hello....here's my working:

    Q/W(Q-W) = A/W + B/(Q-W)

    implies...

    Q = A(Q-W) + BW

    So equating Q's:
    1 = A

    Equating W's:
    0 = -A + B ----> A = B --------> B = 1

    So the expression is:
    1/W + 1/(Q-W)


    I'm interested to know how you could look at it straight away and spot that...I couldn't!
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    (Original post by Worzo)
    Hello....here's my working:

    Q/W(Q-W) = A/W + B/(Q-W)

    implies...

    Q = A(Q-W) + BW

    So equating Q's:
    1 = A

    Equating W's:
    0 = -A + B ----> A = B --------> B = 1

    So the expression is:
    1/W + 1/(Q-W)


    I'm interested to know how you could look at it straight away and spot that...I couldn't!
    lol, yea, thanks, there was a lil mistake which i failed to notice in my calculations. (which then got bigger as this is a part of a bigger quuestion, took me a while to narrow it down to this point. Thanks!)
 
 
 
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Updated: April 10, 2006
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