Hi im doing a question and i have to sketch y=rt(x/x-1) i have never come across one like this before where do i start!
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- Thread Starter
- 11-04-2006 12:51
- 11-04-2006 13:08
you know there are assymtopes at x=1
Just before the assymtope the function => infinity
as x/x-1 => inf when x=>1
then again, I'm not sure if it's valid between 1>x>0 because it goes into i.
Ach, sorry for the useless post
- 11-04-2006 15:04
for anthing in the range (0,1) the top (x) is positive and the bottom (x-1) is negative so it is overall negaitve which means the the root doesn't exist so there is no curve between 0 and 1
outside this range it is always positive and goes to 1 at + and - infinity
at 0 it is 0 so it gradually bends from 0 up to line y = 1 as x goes to -infinity
at 1 it is infinity so it gradualy bends down to the line y = 1 as x goes to infinityLast edited by Retropmot; 11-04-2006 at 15:06.