# fractions again :/Watch

#1
Code:
```x
-----  -  x
x + 1
-------------
x
x  +  -----
x - 1```
thank you, thank you

I can remove x, to get [(1/(x+1)) - 1] / [1 + (1/(x-1))] stuck from there..
0
12 years ago
#2
look at the numerator first, find a common denominator
x - x(x+1)
------------
x

then do the same to the denominator
x(x-1) +x
------------
x-1

now invert the second fraction to multiply to first
and simplify
0
12 years ago
#3
x
----- - x
x + 1
-------------
x
x + -----
x - 1

[x/(x+1) - x ] / [x + x/(x-1)] =
[(x - x(x+1)) / (x+1)] / [ (x(x-1) + x) / (x-1)] =
(x[1-(x+1)])/(x+1) . (x-1) / ( x[1+(x-1)]) =

(x(-x))/(x+1) . (x-1) / ( x(x)) =
(1(-1))/(x+1) . (x-1) / ( 1(1)) =
-(x-1)/(x+1) =
(1-x)/(x+1)
0
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