What do you believe is the hardest topic in chemistry?

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Secret.
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#1
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#1
I'm only talking about Unit 1, what do you think is the hardest sub-topic in chemistry?

e.g. all of organic chemistry or even more sub-topics e.g. Moles, Ionisation energy?


Edit: Actually everything, not only unit 1
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savethegoldfish
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#2
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#2
Equilibrium - I hated how whenever I asked for help, everyone simply repeated le Chatelier's principle at me, which didn't help at all. There was no other explanation, but I assume there must be in A2/degree level. Frustating!
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hollywoodbudgie
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#3
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#3
I've never been a fan of inorganic chemistry.
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Clare~Bear
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#4
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#4
Depends on how you learn/ Sciencey people tend to be best at working things out, therefore the bit where you have to remember and be able to draw out the reactions with the right arrows is the hardest bit.
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aWildPidgey
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#5
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#5
OCR Salters? I thought Hess cycles were hard at first, but then realised that they're really straightforward.
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clumsybear
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#6
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#6
Most of physical chemistry was just :nooo:
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modini
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#7
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#7
The molecular structure of diamonds.

:teehee:
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syhash
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#8
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#8
Moles.

I literally just can't understand it. A-level chemistry will be so much fun.
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Pandabär
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#9
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#9
Equilibrium.

I looooove the organic stuff.
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Little Ant
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#10
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#10
(Original post by hollywoodbudgie)
I've never been a fan of inorganic chemistry.
Who is? Organic chemistry is the sexy stuff!
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oli_G
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#11
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#11
(Original post by savethegoldfish)
Equilibrium - I hated how whenever I asked for help, everyone simply repeated le Chatelier's principle at me, which didn't help at all. There was no other explanation, but I assume there must be in A2/degree level. Frustating!
You get the explanation at A2. It's all to do with entropy (a thermodynamic quantity). Just accept it for now :yep:
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Mollymod
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#12
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#12
(Original post by Little Ant)
Who is? Organic chemistry is the sexy stuff!
Totally agree.

Shall I compare thee to 2-chlorobutane?
Thou art more alkaline and positively charged
Thou glowest lilac in the bunsen flame
And hath a longer carbon chain than 2-iodopropane...

:sexface:
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16dan2life
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#13
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#13
Chem1(AQA) isn't that difficult

Most marks are picked from the calculations which aren't super difficult.

The other chem modules are killers!
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louisjevans
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#14
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#14
For OCR A, the 'suggest' questions on the exam

:unimpressed:
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mclovin123
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#15
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#15
I am doing CHEM4 and it's ok, then I hit ****ING ****TY BUFFERS, OMG **** OFF.

BUFFURS are really rather tricky so far.
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aWildPidgey
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#16
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#16
(Original post by syhash)
Moles.

I literally just can't understand it. A-level chemistry will be so much fun.
1 mole of hydrogen, h2, = 2 grams (about), as 6.022*10^23 atoms of hydrogen is 1 gram (the mass number) so 1*2 (because it's h2) = 2 grams (about).
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gadhvi
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#17
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#17
]I need some help with a chemistry question I've tried loads how do I do it??
7.50x10-3 lol caco3 reacts with 0.200mol dm-3HCI calculate the volume in cm3 of 0.200moldm-3Hcl required to react with 7.50x10-3 of CaCo3
Thanks




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Solid.Snake
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#18
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#18
Out of A level chemistry the topic i absolutely hated was Nuclear Magnetic Resonance spectroscopy and with that spin spin coupling it just gave me nightmares...
I'm just soo glad i don't have to learn all that again!
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Rainingshame
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#19
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#19
(Original post by savethegoldfish)
Equilibrium - I hated how whenever I asked for help, everyone simply repeated le Chatelier's principle at me, which didn't help at all. There was no other explanation, but I assume there must be in A2/degree level. Frustating!
Le Chatallier's principle made it obvious what the answer was. It tries to reverse the action you put on it. e.g. if you increase tempreture it wants to decrease this. To do this it shift equilibrium to the endothermic side so more of the endothermic reaction is taking place and less of the exothermic. This causes a decrease in overall tempreture.
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savethegoldfish
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#20
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#20
(Original post by gadhvi)
]I need some help with a chemistry question I've tried loads how do I do it??
7.50x10-3 lol caco3 reacts with 0.200mol dm-3HCI calculate the volume in cm3 of 0.200moldm-3Hcl required to react with 7.50x10-3 of CaCo3
Thanks
is the CaCo3 given in grams? If so, you can do it.
Use moles=mass/molecular mass to work out the amount of moles of Caco3 there are.
Then, because of the molar ratios in the reaction equation (1:3), you work out you need 3 times as many moles of HCl than CaCo3. Multiply your first calculation and voila, the number of moles.

Put this number into the equation moles=)concentration x volume)/24, to find the volume of HCl required in dm3. Multiply this number by 1000 to find the volume in cm3 instead.
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