# fractions and square rootsWatch

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#1
please can someone show me how to simplify:

a/[Sqrt(a+b)] + b/[Sqrt(a+b)]

thanks, Rev
0
13 years ago
#2
Both terms have common denominator so can be written as

(a+b)/Sqrt(a+b)
= [Sqrt(a+b) x Sqrt(a+b)]/Sqrt(a+b)
= Sqrt(a+b)
0
13 years ago
#3
(Original post by Revelation)
please can someone show me how to simplify:

a/[Sqrt(a+b)] + b/[Sqrt(a+b)]

thanks, Rev
=a/[Sqrt(a+b)] + b/[Sqrt(a+b)]
= a+b/sqrt(a+b)
=[a+b/sqrt(a+b)][sqrt(a+b)/sqrt(a+b)] -- In otherwords rationalizing the denominator by multiplying by sqrt(a+b)/sqrt(a+b)
=(a+b)sqrt(a+b)/(a+b) ----(a+b) cancels top and bottom
=sqrt(a+b)
0
#4
cheers, so for all square roots: Sqrt(x)*Sqrt(x) = x ?

I think algebra is coming back to me now 0
13 years ago
#5
(Original post by Revelation)
cheers, so for all square roots: Sqrt(x)*Sqrt(x) = x ?

I think algebra is coming back to me now yep.
0
13 years ago
#6
(Original post by Revelation)
cheers, so for all square roots: Sqrt(x)*Sqrt(x) = x ?

I think algebra is coming back to me now Yes.
0
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