x Turn on thread page Beta
 You are Here: Home >< Maths

# Help! Part of an area question watch

1. Given that

2d^2 + 1/2 pid^2 = 1/2d^2 theta

show that theta is equal to: 1+1/4pi

thanks!
2. What on earth does that equation mean? What are the d's, what's a "pid" (is that "pi*d"? Is it 1/(2d^2) or (1/2) d^2. You have to be more rigorous with your notation, dude.

Taking my best guess...if you cancel the d^2, then you get theta = pi + 4. But I have no idea what the question means.
3. (Original post by Lawbutwhere?)
Given that

2d^2 + 1/2 pid^2 = 1/2d^2 theta

show that theta is equal to: 1+1/4pi

thanks!
2d²+0.5(pi)d² =0.5d²T
T= 2d²+0.5(pi)d² / 0.5d²
T= 4 + pi

Have you written the question out wrong again? Honestly you do this in all your threads make some effort!
4. Sorry! I am not gd with computers, or writing out equations! Have solved it now! It was:

2d^2 + (1/2)(pi*d^2) = 2d^2theta

so you just divide by 2d^2, to get theta = 1+1/4pi.

Thanks.

Turn on thread page Beta
TSR Support Team

We have a brilliant team of more than 60 Support Team members looking after discussions on The Student Room, helping to make it a fun, safe and useful place to hang out.

This forum is supported by:
Updated: April 11, 2006
Today on TSR

### Did my GCSEs 17 years ago...

... ask me anything!

Poll
Useful resources

## Make your revision easier

### Maths Forum posting guidelines

Not sure where to post? Read the updated guidelines here

### How to use LaTex

Writing equations the easy way

### Study habits of A* students

Top tips from students who have already aced their exams

Can you help? Study help unanswered threads

## Groups associated with this forum:

View associated groups

The Student Room, Get Revising and Marked by Teachers are trading names of The Student Room Group Ltd.

Register Number: 04666380 (England and Wales), VAT No. 806 8067 22 Registered Office: International House, Queens Road, Brighton, BN1 3XE