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    Given that


    2d^2 + 1/2 pid^2 = 1/2d^2 theta

    show that theta is equal to: 1+1/4pi


    thanks!
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    What on earth does that equation mean? What are the d's, what's a "pid" (is that "pi*d"? Is it 1/(2d^2) or (1/2) d^2. You have to be more rigorous with your notation, dude.

    Taking my best guess...if you cancel the d^2, then you get theta = pi + 4. But I have no idea what the question means.
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    (Original post by Lawbutwhere?)
    Given that


    2d^2 + 1/2 pid^2 = 1/2d^2 theta

    show that theta is equal to: 1+1/4pi


    thanks!
    2d²+0.5(pi)d² =0.5d²T
    T= 2d²+0.5(pi)d² / 0.5d²
    T= 4 + pi

    Have you written the question out wrong again? Honestly you do this in all your threads make some effort!
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    Sorry! I am not gd with computers, or writing out equations! Have solved it now! It was:


    2d^2 + (1/2)(pi*d^2) = 2d^2theta

    so you just divide by 2d^2, to get theta = 1+1/4pi.


    Thanks.
 
 
 
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