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    • Thread Starter

    A solid uniform sphere starts from rest and rolls down a 50m high hill. The top half of the hill is rough enough to cause the sphere to roll without slipping, but the lower half is covered with ice and there is no friction. What is the translational speed of the sphere when it reaches the bottom of the hill?

    Now I know that we must have to use energy methods to solve this problem, and that for the top half of the hill the gpe is converted to kinetic and rotational energy. However, for the bottom half of the hill where there is no friction the sphere will slip so I am slightly confused as to what happens.

    Thanks for any help.
    • Thread Starter

    Ok....i think I have solved the question and i get the translational speed at the bottom of the hill to be the square root of 840 which is approximately 29 metres per second. If anyone can confirm this answer is correct it would be very helpful.
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Updated: April 12, 2006
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