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# integration watch

1. How can you integrate the following:

∫e^(2x) sinx dx ?

I can't seem to do it by parts, using u=e^(2x).

Cheers
2. You have to do it by parts twice, so on the RHS you get back to something of the form:

{something something} + A[∫e^(2x) sinx dx], where A is a constant

Then you take the A[∫e^(2x) sinx dx] over to the LHS and subtract it from the ∫e^(2x) sinx dx that's already there. It's better if you try it rather than me explaining it.

Just remember to keep the same term the differentiable one (e^2x in this case) on the second time of doing parts.
3. Thanks a lot mate.

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Updated: April 13, 2006
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