sarah12345
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Hi just a quick question im havin trouble with

the polar equation of a curve is r^2=a rt2 (cos theta)

put this into cartesian form

thanks alot
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7589200
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r^2 = a rt2 (x/r)
r^3 = a rt2 x
(x^2 + y^2)^(3/2) = a rt2 x
(x^2 + y^2)^3 = 2a^2 x^2

Not sure though.
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Christophicus
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(Original post by sarah12345)
Hi just a quick question im havin trouble with

the polar equation of a curve is r^2=a rt2 (cos theta)

put this into cartesian form

thanks alot
r^2 = a.rt2.cos\theta

x^2 + y^2 = r^2
x = rcos\theta
y = rsin\theta

=> x^2 + y^2 = a.rt2.x/r
=> r(x^2+y^2) = a.rt2.x
=> (x^2+y^2)^0.5.(x^2+y^2) = art2.x
=> (x^2+y^2)^(3/2) = a.rt2.x
=> (x^2+y^2)^3 = 2a^2.x^2

I think that's right.
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