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    Could some one please give me the products of this reaction:

    Sodium Iodide + Sulphuric acid -->

    There are several products made, but which ones do you list? All of them?

    Thanks
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    I thought this was one of those awful reactions that changes drastically depending on conditions or the nature of the reagents...

    I've seen 2 NaI + H2SO4 ==> l2 + Na2SO4 + H2,

    but I think in a steady supply of oxygen, it might go to:

    NaI + H2SO4 ==> NaHSO4 + HI

    Surely you've taken notes on this reaction?? Or have a textbook??
    And if they ask for the products, I'm sure they want all of them - having an unbalanced chemical equation is useless!!
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    The thing is I looked on chemguide.co.uk and it says that one product leads to the other. This is what it says

    The reduction of the sulphuric acid is more complicated than before. The iodide ions are powerful enough reducing agents to reduce it

    first to sulphur dioxide (sulphur oxidation state = +4)

    then to sulphur itself (oxidation state = 0)

    and all the way to hydrogen sulphide (sulphur oxidation state = -2).


    So, what do I include?
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    (Original post by DartsOfPleasure)
    The thing is I looked on chemguide.co.uk and it says that one product leads to the other. This is what it says

    The reduction of the sulphuric acid is more complicated than before. The iodide ions are powerful enough reducing agents to reduce it

    first to sulphur dioxide (sulphur oxidation state = +4)

    then to sulphur itself (oxidation state = 0)

    and all the way to hydrogen sulphide (sulphur oxidation state = -2).


    So, what do I include?
    I would put the overall equation for the whole reaction going as far as it can - so put H2S as the product.
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    (Original post by DartsOfPleasure)
    Could some one please give me the products of this reaction:

    Sodium Iodide + Sulphuric acid -->

    There are several products made, but which ones do you list? All of them?
    Looks like its a redox reaction with sulphuric acid acting as a catalyst.

    2I- -> I2 + 2e-
    2Na+ + 2e- -> 2Na

    So products are iodine gas and sodium solid. [Not sure though]
 
 
 
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