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    Hi, please can you check my answer to this question, I've attatched the diagram.
    The question is: Prove that APB and APC are congruent (3 marks)
    A B and C are points on the circumference, angle ABC= and ACB, PB and PC are tangents.

    Answer:
    BP = CP (the lengths of tangents from a point are equal
    Both triangles share the side AP
    ABC=ACB and so ABC must be isosceles, and AB=AC

    Therefore the triangles APC and APB must be congruent (SSS rule)
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    And would angle ABC be 50 degrees?? =/
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    You didn't attach anything...Can you attach it?
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    lmao. sorry, i've attatched it now.
    • Thread Starter
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    anyone? please can someone just check over my answer?
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    Yeah it's correct.
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    Thanks very much =]
 
 
 
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Updated: April 17, 2006
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